Newton second equation apply
s=ut+1/2at^2
but in question accel. is retarding so eqution:-
s=ut-1/2at^2 put all given data we get
distqnce = 4 meter

**Given:**
Initial velocity (u) = 5 m/sec
Acceleration (a) = -2 m/sec^2 (negative because it is retardation)
Time (t) = 4 sec

**To find:**
Distance traveled in 4 seconds

**Formula:**
The equation of motion to find distance (s) is given by:
s = ut + (1/2)at^2

**Calculation:**
Substituting the given values into the equation of motion:
s = (5 * 4) + (1/2)(-2)(4^2)
s = 20 + (-16)
s = 4 meters

**Explanation:**
To find the distance traveled by the particle, we use the equation of motion: s = ut + (1/2)at^2.
Here, u represents the initial velocity, a represents the acceleration, and t represents the time.

In this case, the initial velocity is 5 m/sec and the acceleration is -2 m/sec^2. The negative sign indicates retardation.

Substituting the given values into the equation, we get:
s = (5 * 4) + (1/2)(-2)(4^2)

Simplifying the equation:
s = 20 + (-16)
s = 4 meters

Therefore, the distance traveled by the particle in 4 seconds is 4 meters.

**Conclusion:**
The particle travels a distance of 4 meters in 4 seconds with an initial velocity of 5 m/sec and retardation of 2 m/sec^2.