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Two spheres A and B of radius a and b respectively are at same electric potential. The ratio of the surface charge densities of A and B is .?
Most Upvoted Answer
Two spheres A and B of radius a and b respectively are at same electri...
Explanation:

When two conducting spheres A and B of radius a and b respectively are at the same electric potential, the ratio of surface charge densities of A and B can be found using the following formula:

Formula:

Surface charge density = Q / A

where Q is the charge on the sphere and A is the surface area of the sphere.

Calculation:

Let the charge on sphere A be Qa and the charge on sphere B be Qb.

Since both the spheres are at the same potential, the potential difference between them is zero.

Hence, we have:

Va - Vb = 0

or

(kQa / a) - (kQb / b) = 0

where k is the Coulomb's constant.

Solving for Qa / Qb, we get:

Qa / Qb = (a / b)

Now, using the formula for surface charge density, we have:

Surface charge density of A = Qa / (4πa²)

Surface charge density of B = Qb / (4πb²)

Substituting the value of Qa / Qb, we get:

Surface charge density of A / Surface charge density of B = (Qa / (4πa²)) / (Qb / (4πb²))

= (a / b) * (b² / a²)

= b / a

Hence, the ratio of surface charge densities of A and B is b / a.

Conclusion:

The ratio of surface charge densities of two spheres A and B of radii a and b respectively, when they are at the same electric potential, is given by b / a.
Community Answer
Two spheres A and B of radius a and b respectively are at same electri...
Ratio is b/a.
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Two spheres A and B of radius a and b respectively are at same electric potential. The ratio of the surface charge densities of A and B is .?
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