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An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons be accelerated so that its wavelength becomes equal to 1.54 Angstrom? 1-63.2V 2-126.4V 3-31.6V 4-632V
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An electron beam can undergo diffraction by crystals. Through what pot...
Calculating Accelerating Potential for Electron Beam Diffraction
To determine the accelerating potential required for an electron beam to have a wavelength of 1.54 Angstroms, we can use the de Broglie wavelength equation:
λ = h / √(2mE)
where:
- λ is the wavelength (1.54 Angstroms)
- h is the Planck constant (6.626 x 10^-34 m^2 kg / s)
- m is the mass of an electron (9.11 x 10^-31 kg)
- E is the accelerating potential (in volts)
By rearranging the equation, we can solve for E:
E = h^2 / (2mλ^2)
After substituting the given values, we get:
E = (6.626 x 10^-34)^2 / (2 * 9.11 x 10^-31 * (1.54 x 10^-10)^2)
E ≈ 63.2 V
Therefore, the accelerating potential needed for the electron beam to have a wavelength of 1.54 Angstroms is approximately 63.2 volts.
Options:
1. 63.2V
2. 126.4V
3. 31.6V
4. 632V
The correct answer is 63.2V.
To determine the accelerating potential required for an electron beam to have a wavelength of 1.54 Angstroms, we can use the de Broglie wavelength equation:
λ = h / √(2mE)
where:
- λ is the wavelength (1.54 Angstroms)
- h is the Planck constant (6.626 x 10^-34 m^2 kg / s)
- m is the mass of an electron (9.11 x 10^-31 kg)
- E is the accelerating potential (in volts)
By rearranging the equation, we can solve for E:
E = h^2 / (2mλ^2)
After substituting the given values, we get:
E = (6.626 x 10^-34)^2 / (2 * 9.11 x 10^-31 * (1.54 x 10^-10)^2)
E ≈ 63.2 V
Therefore, the accelerating potential needed for the electron beam to have a wavelength of 1.54 Angstroms is approximately 63.2 volts.
Options:
1. 63.2V
2. 126.4V
3. 31.6V
4. 632V
The correct answer is 63.2V.
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An electron beam can undergo diffraction by crystals. Through what pot...
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An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons be accelerated so that its wavelength becomes equal to 1.54 Angstrom? 1-63.2V 2-126.4V 3-31.6V 4-632V
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An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons be accelerated so that its wavelength becomes equal to 1.54 Angstrom? 1-63.2V 2-126.4V 3-31.6V 4-632V for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons be accelerated so that its wavelength becomes equal to 1.54 Angstrom? 1-63.2V 2-126.4V 3-31.6V 4-632V covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons be accelerated so that its wavelength becomes equal to 1.54 Angstrom? 1-63.2V 2-126.4V 3-31.6V 4-632V.
An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons be accelerated so that its wavelength becomes equal to 1.54 Angstrom? 1-63.2V 2-126.4V 3-31.6V 4-632V for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons be accelerated so that its wavelength becomes equal to 1.54 Angstrom? 1-63.2V 2-126.4V 3-31.6V 4-632V covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons be accelerated so that its wavelength becomes equal to 1.54 Angstrom? 1-63.2V 2-126.4V 3-31.6V 4-632V.
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