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The molal freezing point constant for water is 1.86°C/mole. If 342 gm of cane sugar (C₁₂H₂₂O₁₁) is dissolved in 1000 g of water, the solution will freeze at
- a)-1.86°C
- b)1.86°C
- c)-3.92°C
- d)2.42°C
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
The molal freezing point constant for water is 1.86°C/mole. If 342...
ΔTf=−kfm
molality of solution = (342/342)=1
ΔTf=−1.86×(342/342)/1=−1.86oC so option A is correct
molality of solution = (342/342)=1
ΔTf=−1.86×(342/342)/1=−1.86oC so option A is correct
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The molal freezing point constant for water is 1.86°C/mole. If 342 gm of cane sugar (CHO) is dissolved in 1000 g of water, the solution will freeze ata)-1.86°Cb)1.86°Cc)-3.92°Cd)2.42°CCorrect answer is option 'A'. Can you explain this answer?
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The molal freezing point constant for water is 1.86°C/mole. If 342 gm of cane sugar (CHO) is dissolved in 1000 g of water, the solution will freeze ata)-1.86°Cb)1.86°Cc)-3.92°Cd)2.42°CCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The molal freezing point constant for water is 1.86°C/mole. If 342 gm of cane sugar (CHO) is dissolved in 1000 g of water, the solution will freeze ata)-1.86°Cb)1.86°Cc)-3.92°Cd)2.42°CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The molal freezing point constant for water is 1.86°C/mole. If 342 gm of cane sugar (CHO) is dissolved in 1000 g of water, the solution will freeze ata)-1.86°Cb)1.86°Cc)-3.92°Cd)2.42°CCorrect answer is option 'A'. Can you explain this answer?.
The molal freezing point constant for water is 1.86°C/mole. If 342 gm of cane sugar (CHO) is dissolved in 1000 g of water, the solution will freeze ata)-1.86°Cb)1.86°Cc)-3.92°Cd)2.42°CCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The molal freezing point constant for water is 1.86°C/mole. If 342 gm of cane sugar (CHO) is dissolved in 1000 g of water, the solution will freeze ata)-1.86°Cb)1.86°Cc)-3.92°Cd)2.42°CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The molal freezing point constant for water is 1.86°C/mole. If 342 gm of cane sugar (CHO) is dissolved in 1000 g of water, the solution will freeze ata)-1.86°Cb)1.86°Cc)-3.92°Cd)2.42°CCorrect answer is option 'A'. Can you explain this answer?.
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