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The number of moles of KMno4 reduced by one mole of KI in alkaline medium is (a) 1/5 (b) 2 (c) 5 (d) 2.5
correct answer is b then explain the answer?
correct answer is b then explain the answer?
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Explanation:
Redox Reaction:
- The reaction between KMnO4 and KI in alkaline medium can be represented as follows:
2KMnO4 + 10KI + 8OH- → 2K2MnO4 + 5I2 + 6H2O
- In this reaction, each mole of KI reduces one mole of KMnO4.
Molar Ratios:
- From the balanced equation, it can be seen that 10 moles of KI are required to reduce 2 moles of KMnO4.
- Therefore, the ratio of moles of KMnO4 reduced by 1 mole of KI is 2/10 = 1/5.
Answer:
- The number of moles of KMnO4 reduced by one mole of KI in alkaline medium is 1/5.
Therefore, the correct answer is (a) 1/5.
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The number of moles of KMno4 reduced by one mole of KI in alkaline medium is (a) 1/5 (b) 2 (c) 5 (d) 2.5correct answer is b then explain the answer?
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