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5 moles of A, 6 moles of Z are mixed with sufficient amount of C to finally produce F. Then find the maximum moles of F which can be produced. Assuming that the product formed can also be reused. Reactions are: A 2Z→ B …(i) B C→ Z F .(ii) (1) 3 moles (2) 4.5 moles (3) 5 moles (4) 6 mole?
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5 moles of A, 6 moles of Z are mixed with sufficient amount of C to fi...
**Given:**
- 5 moles of A
- 6 moles of Z
**Reactions:**
1. A + 2Z → B
2. B + C → Z + F
To find the maximum moles of F that can be produced, we need to determine the limiting reactant and the stoichiometry of the reactions.
**Determine the Limiting Reactant:**
To find the limiting reactant, we need to compare the moles of A and Z to the stoichiometry of reaction (i).
From the reaction (i), we can see that 1 mole of A reacts with 2 moles of Z, so the number of moles of Z required for 5 moles of A is (5 moles A) * (2 moles Z / 1 mole A) = 10 moles Z.
Since we only have 6 moles of Z, it is the limiting reactant in this case.
**Determine the Maximum Moles of F:**
To determine the maximum moles of F, we need to consider the stoichiometry of reaction (ii).
From reaction (ii), we can see that 1 mole of B reacts with 1 mole of C to produce 1 mole of Z and 1 mole of F.
Since the limiting reactant is Z, we can calculate the number of moles of F produced using the stoichiometry of reaction (ii) and the moles of Z available.
The number of moles of F produced is (6 moles Z) * (1 mole F / 1 mole Z) = 6 moles F.
Therefore, the maximum moles of F that can be produced is 6 moles.
**Answer:**
The maximum moles of F that can be produced is 6 moles.
- 5 moles of A
- 6 moles of Z
**Reactions:**
1. A + 2Z → B
2. B + C → Z + F
To find the maximum moles of F that can be produced, we need to determine the limiting reactant and the stoichiometry of the reactions.
**Determine the Limiting Reactant:**
To find the limiting reactant, we need to compare the moles of A and Z to the stoichiometry of reaction (i).
From the reaction (i), we can see that 1 mole of A reacts with 2 moles of Z, so the number of moles of Z required for 5 moles of A is (5 moles A) * (2 moles Z / 1 mole A) = 10 moles Z.
Since we only have 6 moles of Z, it is the limiting reactant in this case.
**Determine the Maximum Moles of F:**
To determine the maximum moles of F, we need to consider the stoichiometry of reaction (ii).
From reaction (ii), we can see that 1 mole of B reacts with 1 mole of C to produce 1 mole of Z and 1 mole of F.
Since the limiting reactant is Z, we can calculate the number of moles of F produced using the stoichiometry of reaction (ii) and the moles of Z available.
The number of moles of F produced is (6 moles Z) * (1 mole F / 1 mole Z) = 6 moles F.
Therefore, the maximum moles of F that can be produced is 6 moles.
**Answer:**
The maximum moles of F that can be produced is 6 moles.
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5 moles of A, 6 moles of Z are mixed with sufficient amount of C to finally produce F. Then find the maximum moles of F which can be produced. Assuming that the product formed can also be reused. Reactions are: A 2Z→ B …(i) B C→ Z F .(ii) (1) 3 moles (2) 4.5 moles (3) 5 moles (4) 6 mole?
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5 moles of A, 6 moles of Z are mixed with sufficient amount of C to finally produce F. Then find the maximum moles of F which can be produced. Assuming that the product formed can also be reused. Reactions are: A 2Z→ B …(i) B C→ Z F .(ii) (1) 3 moles (2) 4.5 moles (3) 5 moles (4) 6 mole? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 5 moles of A, 6 moles of Z are mixed with sufficient amount of C to finally produce F. Then find the maximum moles of F which can be produced. Assuming that the product formed can also be reused. Reactions are: A 2Z→ B …(i) B C→ Z F .(ii) (1) 3 moles (2) 4.5 moles (3) 5 moles (4) 6 mole? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 5 moles of A, 6 moles of Z are mixed with sufficient amount of C to finally produce F. Then find the maximum moles of F which can be produced. Assuming that the product formed can also be reused. Reactions are: A 2Z→ B …(i) B C→ Z F .(ii) (1) 3 moles (2) 4.5 moles (3) 5 moles (4) 6 mole?.
5 moles of A, 6 moles of Z are mixed with sufficient amount of C to finally produce F. Then find the maximum moles of F which can be produced. Assuming that the product formed can also be reused. Reactions are: A 2Z→ B …(i) B C→ Z F .(ii) (1) 3 moles (2) 4.5 moles (3) 5 moles (4) 6 mole? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 5 moles of A, 6 moles of Z are mixed with sufficient amount of C to finally produce F. Then find the maximum moles of F which can be produced. Assuming that the product formed can also be reused. Reactions are: A 2Z→ B …(i) B C→ Z F .(ii) (1) 3 moles (2) 4.5 moles (3) 5 moles (4) 6 mole? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 5 moles of A, 6 moles of Z are mixed with sufficient amount of C to finally produce F. Then find the maximum moles of F which can be produced. Assuming that the product formed can also be reused. Reactions are: A 2Z→ B …(i) B C→ Z F .(ii) (1) 3 moles (2) 4.5 moles (3) 5 moles (4) 6 mole?.
Solutions for 5 moles of A, 6 moles of Z are mixed with sufficient amount of C to finally produce F. Then find the maximum moles of F which can be produced. Assuming that the product formed can also be reused. Reactions are: A 2Z→ B …(i) B C→ Z F .(ii) (1) 3 moles (2) 4.5 moles (3) 5 moles (4) 6 mole? in English & in Hindi are available as part of our courses for NEET.
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