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Which one of the following is the strongest oxidising agent ?
  • a)
    HClO
  • b)
    HClO2
  • c)
    HClO3
  • d)
    HClO4
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Which one of the following is the strongest oxidising agent ?a)HClOb)H...
Strongest Oxidizing Agent among HCl, HClO2, HClO3, and HClO4

Heading: Definition of Oxidizing Agent

An oxidizing agent is a substance that can accept electrons from another substance during a redox reaction. It is itself reduced while oxidizing the other substance.

Heading: Comparing HCl, HClO2, HClO3, and HClO4

Among the given options, HCl is the strongest oxidizing agent. This is because it has the highest oxidation state of +1 for chlorine, and therefore, it can easily accept electrons from other substances.

Heading: Explanation

The oxidation state of chlorine in HCl is -1. In HClO2, the oxidation state of chlorine is +3, in HClO3 it is +5, and in HClO4 it is +7. The higher the oxidation state of an element, the stronger is its oxidizing power. Therefore, HClO4 should be the strongest oxidizing agent among the given options.

However, this is not the case because HClO4 is a highly reactive and unstable compound. It can react violently with organic compounds and even with water, releasing heat and oxygen. Therefore, it is not suitable for most practical applications.

On the other hand, HCl is a stable and widely used oxidizing agent. It can react with metals, non-metals, and organic compounds to produce different products. For example, it can oxidize iron to form iron(III) chloride, sulfur to form sulfur dioxide, and ethanol to form acetaldehyde.

Therefore, among the given options, HCl is the strongest oxidizing agent that is safe and practical to use.
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Community Answer
Which one of the following is the strongest oxidising agent ?a)HClOb)H...
Strongest oxidising agent HClO
HClO>HClO2>HClO3>HClO4
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Which one of the following is the strongest oxidising agent ?a)HClOb)HClO2c)HClO3d)HClO4Correct answer is option 'A'. Can you explain this answer?
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