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 A uniform wire of resistance R and length L is cut into four equal parts, each of length L/4 which are then connected in parallel combination.
The effective resistance of the combination will be
  • a)
    R
  • b)
    4R
  • c)
    R/4
  • d)
    R/16
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A uniform wire of resistance R and length L is cut into four equal par...
As , resistance is directly proportional to length , the resistance of each part is R/4 , so when they are all connected in parallel, the resistance further become one fourth . Thus , the new resistance is R/16

Means ... 1/Reff = 1/R÷4 + 1/R÷4 + 1/R÷4 + 1/R÷4
1/Reff = 4/R + 4/R + 4/R + 4/R
Reff = R/16 ...ans...

$$Hope it's help... $$
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Community Answer
A uniform wire of resistance R and length L is cut into four equal par...
Solution:

Resistance of a wire is given by the formula,

R = ρL/A, where ρ is resistivity of the material, L is length and A is area of cross section

When the uniform wire of resistance R and length L is cut into four equal parts, each of length L/4, the resistance of each part is given by

R' = ρL/4/A

As the four parts are connected in parallel, the effective resistance of the combination is given by

1/R_total = 1/R' + 1/R' + 1/R' + 1/R'

1/R_total = 4/R'

R_total = R'/4

Substituting the value of R' in the above equation, we get

R_total = ρL/4A/4

R_total = ρL/16A

R_total = R/16

Therefore, the effective resistance of the combination is R/16.

Hence, the correct option is (d) R/16.
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A uniform wire of resistance R and length L is cut into four equal parts, each of length L/4 which are then connected in parallel combination.The effective resistance of the combination will bea)Rb)4Rc)R/4d)R/16Correct answer is option 'D'. Can you explain this answer?
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