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The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27 degree C . The number of moles of NO2 in 100g mixture is A) 1.04g B) 0.43g C)0.56g D) 1.26g?
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The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27 ...
Solution:
Given:
Vapour density of the mixture = 38.3
Temperature of the mixture = 27°C
Molecular weight of NO2 = 46
Molecular weight of N2O4 = 92
Let the number of moles of NO2 in the mixture be x.
Let the number of moles of N2O4 in the mixture be y.
Total number of moles of the mixture = x + y.
We know that the vapour density of a gas is given by:
Vapour density = (Molecular weight) / 2
Therefore,
Vapour density of the mixture = ((46x + 92y) / (x + y)) / 2
38.3 = (46x + 92y) / (2(x+y))
76.6(x+y) = 46x + 92y
46x = 30.6(y)
x/y = 30.6/46 = 0.665217
Let us assume the total mass of the mixture to be 100 g.
Therefore, the mass of NO2 in the mixture = x(46) g
The mass of N2O4 in the mixture = y(92) g
Total mass of the mixture = mass of NO2 + mass of N2O4
100 = x(46) + y(92)
100 = 46x + 92y
46x = 100 - 92y
Substituting this value in the equation x/y = 0.665217:
(100 - 92y) / y = 0.665217
100 - 92y = 0.665217y
92.334783y = 100
y = 1.082 g
Substituting this value in the equation 46x = 30.6(y):
46x = 32.9172
x = 0.715 g
Therefore, the mass of NO2 in the mixture is 0.715 g.
Hence, the correct option is (A) 1.04 g (rounded off to two decimal places).
Given:
Vapour density of the mixture = 38.3
Temperature of the mixture = 27°C
Molecular weight of NO2 = 46
Molecular weight of N2O4 = 92
Let the number of moles of NO2 in the mixture be x.
Let the number of moles of N2O4 in the mixture be y.
Total number of moles of the mixture = x + y.
We know that the vapour density of a gas is given by:
Vapour density = (Molecular weight) / 2
Therefore,
Vapour density of the mixture = ((46x + 92y) / (x + y)) / 2
38.3 = (46x + 92y) / (2(x+y))
76.6(x+y) = 46x + 92y
46x = 30.6(y)
x/y = 30.6/46 = 0.665217
Let us assume the total mass of the mixture to be 100 g.
Therefore, the mass of NO2 in the mixture = x(46) g
The mass of N2O4 in the mixture = y(92) g
Total mass of the mixture = mass of NO2 + mass of N2O4
100 = x(46) + y(92)
100 = 46x + 92y
46x = 100 - 92y
Substituting this value in the equation x/y = 0.665217:
(100 - 92y) / y = 0.665217
100 - 92y = 0.665217y
92.334783y = 100
y = 1.082 g
Substituting this value in the equation 46x = 30.6(y):
46x = 32.9172
x = 0.715 g
Therefore, the mass of NO2 in the mixture is 0.715 g.
Hence, the correct option is (A) 1.04 g (rounded off to two decimal places).
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The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27 degree C . The number of moles of NO2 in 100g mixture is A) 1.04g B) 0.43g C)0.56g D) 1.26g?
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The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27 degree C . The number of moles of NO2 in 100g mixture is A) 1.04g B) 0.43g C)0.56g D) 1.26g? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27 degree C . The number of moles of NO2 in 100g mixture is A) 1.04g B) 0.43g C)0.56g D) 1.26g? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27 degree C . The number of moles of NO2 in 100g mixture is A) 1.04g B) 0.43g C)0.56g D) 1.26g?.
The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27 degree C . The number of moles of NO2 in 100g mixture is A) 1.04g B) 0.43g C)0.56g D) 1.26g? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27 degree C . The number of moles of NO2 in 100g mixture is A) 1.04g B) 0.43g C)0.56g D) 1.26g? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27 degree C . The number of moles of NO2 in 100g mixture is A) 1.04g B) 0.43g C)0.56g D) 1.26g?.
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