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In an electrical circuit two resistors of 2 ohm and 4 ohm respectively are connected in parallel to a 6V battery. The heat dissipated by 4 ohm resistor in 5 second will be (a)45J(b)20J(c)60J(d)35J. Please any one explain me this with correct answer.?
Most Upvoted Answer
In an electrical circuit two resistors of 2 ohm and 4 ohm respectively...
Two resistors 2 Ωand 4 Ω are connected in series . so the total resistance is 6 ohm
given v=6v
I = V/R
I = 6/6
I = 1 A
new R = 4Ω
t=5 sec
H = I²Rt
H = 1²(4)(5)
H = 20 Joule.
Hence, option b is correct.
given v=6v
I = V/R
I = 6/6
I = 1 A
new R = 4Ω
t=5 sec
H = I²Rt
H = 1²(4)(5)
H = 20 Joule.
Hence, option b is correct.
Community Answer
In an electrical circuit two resistors of 2 ohm and 4 ohm respectively...
Given:
- Two resistors of 2 ohm and 4 ohm respectively
- Resistors are connected in parallel
- Battery voltage = 6V
- Time = 5 seconds
To Find:
- Heat dissipated by the 4 ohm resistor in 5 seconds
Solution:
Step 1: Calculate the equivalent resistance (Requiv) of the parallel circuit:
- The formula to calculate the equivalent resistance of resistors connected in parallel is:
1/Requiv = 1/R1 + 1/R2 + 1/R3 + ...
- In this case, we have two resistors in parallel (R1 = 2 ohm, R2 = 4 ohm):
1/Requiv = 1/2 + 1/4
1/Requiv = 2/4 + 1/4
1/Requiv = 3/4
- Taking the reciprocal on both sides:
Requiv = 4/3 ohm
Step 2: Calculate the current flowing through the resistors:
- Ohm's Law states that the current (I) flowing through a resistor is given by the equation:
I = V/R
- In this case, the battery voltage is 6V and the equivalent resistance is 4/3 ohm:
I = 6 / (4/3)
I = 6 * (3/4)
I = 18/4
I = 4.5 A
Step 3: Calculate the heat dissipated by the 4 ohm resistor:
- The formula to calculate the heat dissipated by a resistor is given by the equation:
Heat (H) = I^2 * R * t
- In this case, the resistance is 4 ohm and the time is 5 seconds:
H = (4.5)^2 * 4 * 5
H = 20.25 * 4 * 5
H = 405 * 5
H = 2025 J
Therefore, the heat dissipated by the 4 ohm resistor in 5 seconds is 2025 J.
Answer:
The correct option is (d) 2025 J
- Two resistors of 2 ohm and 4 ohm respectively
- Resistors are connected in parallel
- Battery voltage = 6V
- Time = 5 seconds
To Find:
- Heat dissipated by the 4 ohm resistor in 5 seconds
Solution:
Step 1: Calculate the equivalent resistance (Requiv) of the parallel circuit:
- The formula to calculate the equivalent resistance of resistors connected in parallel is:
1/Requiv = 1/R1 + 1/R2 + 1/R3 + ...
- In this case, we have two resistors in parallel (R1 = 2 ohm, R2 = 4 ohm):
1/Requiv = 1/2 + 1/4
1/Requiv = 2/4 + 1/4
1/Requiv = 3/4
- Taking the reciprocal on both sides:
Requiv = 4/3 ohm
Step 2: Calculate the current flowing through the resistors:
- Ohm's Law states that the current (I) flowing through a resistor is given by the equation:
I = V/R
- In this case, the battery voltage is 6V and the equivalent resistance is 4/3 ohm:
I = 6 / (4/3)
I = 6 * (3/4)
I = 18/4
I = 4.5 A
Step 3: Calculate the heat dissipated by the 4 ohm resistor:
- The formula to calculate the heat dissipated by a resistor is given by the equation:
Heat (H) = I^2 * R * t
- In this case, the resistance is 4 ohm and the time is 5 seconds:
H = (4.5)^2 * 4 * 5
H = 20.25 * 4 * 5
H = 405 * 5
H = 2025 J
Therefore, the heat dissipated by the 4 ohm resistor in 5 seconds is 2025 J.
Answer:
The correct option is (d) 2025 J
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In an electrical circuit two resistors of 2 ohm and 4 ohm respectively are connected in parallel to a 6V battery. The heat dissipated by 4 ohm resistor in 5 second will be (a)45J(b)20J(c)60J(d)35J. Please any one explain me this with correct answer.?
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In an electrical circuit two resistors of 2 ohm and 4 ohm respectively are connected in parallel to a 6V battery. The heat dissipated by 4 ohm resistor in 5 second will be (a)45J(b)20J(c)60J(d)35J. Please any one explain me this with correct answer.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about In an electrical circuit two resistors of 2 ohm and 4 ohm respectively are connected in parallel to a 6V battery. The heat dissipated by 4 ohm resistor in 5 second will be (a)45J(b)20J(c)60J(d)35J. Please any one explain me this with correct answer.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an electrical circuit two resistors of 2 ohm and 4 ohm respectively are connected in parallel to a 6V battery. The heat dissipated by 4 ohm resistor in 5 second will be (a)45J(b)20J(c)60J(d)35J. Please any one explain me this with correct answer.?.
In an electrical circuit two resistors of 2 ohm and 4 ohm respectively are connected in parallel to a 6V battery. The heat dissipated by 4 ohm resistor in 5 second will be (a)45J(b)20J(c)60J(d)35J. Please any one explain me this with correct answer.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about In an electrical circuit two resistors of 2 ohm and 4 ohm respectively are connected in parallel to a 6V battery. The heat dissipated by 4 ohm resistor in 5 second will be (a)45J(b)20J(c)60J(d)35J. Please any one explain me this with correct answer.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an electrical circuit two resistors of 2 ohm and 4 ohm respectively are connected in parallel to a 6V battery. The heat dissipated by 4 ohm resistor in 5 second will be (a)45J(b)20J(c)60J(d)35J. Please any one explain me this with correct answer.?.
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In an electrical circuit two resistors of 2 ohm and 4 ohm respectively are connected in parallel to a 6V battery. The heat dissipated by 4 ohm resistor in 5 second will be (a)45J(b)20J(c)60J(d)35J. Please any one explain me this with correct answer.?, a detailed solution for In an electrical circuit two resistors of 2 ohm and 4 ohm respectively are connected in parallel to a 6V battery. The heat dissipated by 4 ohm resistor in 5 second will be (a)45J(b)20J(c)60J(d)35J. Please any one explain me this with correct answer.? has been provided alongside types of In an electrical circuit two resistors of 2 ohm and 4 ohm respectively are connected in parallel to a 6V battery. The heat dissipated by 4 ohm resistor in 5 second will be (a)45J(b)20J(c)60J(d)35J. Please any one explain me this with correct answer.? theory, EduRev gives you an
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