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How to find bond order of radicals like So4*-2 and ClO4-?
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How to find bond order of radicals like So4*-2 and ClO4-?
Guide to Finding Bond Order of Radicals
Introduction
In chemistry, bond order is defined as the number of chemical bonds between a pair of atoms. It indicates the stability of a molecule and is determined by the number of electrons in the bonding and anti-bonding orbitals. In this guide, we will discuss how to find the bond order of radicals such as SO4*-2 and ClO4-.
Steps to Find Bond Order
- Determine the Lewis structure: The first step in finding bond order is to draw the Lewis structure of the radical. This will help determine the number of electrons in the bonding and anti-bonding orbitals.
- Count the number of electrons: The next step is to count the total number of electrons in the molecule. This can be done by adding the valence electrons of all the atoms present in the molecule.
- Determine the number of bonding and anti-bonding electrons: Using the Lewis structure, you can determine the number of electrons in the bonding and anti-bonding orbitals. The bonding electrons are those that are shared between the atoms, while the anti-bonding electrons are those that are not shared.
- Calculate bond order: Once the number of bonding and anti-bonding electrons is determined, the bond order can be calculated using the formula:
Bond Order = (Number of bonding electrons - Number of anti-bonding electrons) / 2
A bond order of 0 indicates that there is no bond between the atoms, while a bond order of 1 indicates a single bond, 2 indicates a double bond, and so on.
Example: SO4*-2
- The Lewis structure of SO4*-2 can be drawn as follows:
O
||
O-S-O(-)
||
O
The negative charge indicates the presence of an extra electron. - The total number of electrons in SO4*-2 is:
6 (Oxygen) + 6 (Oxygen) + 6 (Sulfur) + 2 (Extra electron) = 20 - The number of bonding and anti-bonding electrons can be determined as follows:
Bonding electrons = 8 (4 double bonds)
Anti-bonding electrons = 4 (2 lone pairs)
Therefore, the bond order of SO4*-2 is:
Bond Order = (8 - 4) / 2 = 2
Example: ClO4-
- The Lewis structure of ClO4- can be drawn as follows:
O
||
O-Cl-O(-)
||
O
||
O
The negative charge indicates the presence of an extra electron. - The total number of electrons in ClO4- is:
7 (Chlorine) + 4 (Oxygen) + 1 (Extra electron) = 32 - The number of bonding and anti-bonding electrons can be determined as follows:
Bonding electrons = 10 (4 single bonds and 3 double bonds
Community Answer
How to find bond order of radicals like So4*-2 and ClO4-?
It is to remember, RATIO OF No of bonds formed by central atom to no of surrounding atoms... for example So4*-2, central atom forms 6 bonds with four oxygen atoms.... 6/4=1.5 same method is used find out the remaining ones..
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How to find bond order of radicals like So4*-2 and ClO4-?
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How to find bond order of radicals like So4*-2 and ClO4-? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about How to find bond order of radicals like So4*-2 and ClO4-? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How to find bond order of radicals like So4*-2 and ClO4-?.
How to find bond order of radicals like So4*-2 and ClO4-? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about How to find bond order of radicals like So4*-2 and ClO4-? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How to find bond order of radicals like So4*-2 and ClO4-?.
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