A bag contained a mixture of wheat flour and gram flour in the ratio 5...
Let the quantity of wheat flour and gram flour in the bag be ‘5x’ kg and ‘2x’ kg
By adding 3 kg of wheat flour, the ratio becomes 11 ∶ 4
⇒ (5x + 3)/2x = 11/4
⇒ 20x + 12 = 22x
⇒ 2x = 12
⇒ x = 12/2 = 6 kg
⇒ Quantity of wheat flour in bag = 5x = 5 × 6 = 30 kg
⇒ Quantity of gram flour in bag = 2x = 2 × 6 = 12 kg
Now,
Let ‘y’ kg of gram flour be added to obtain a mixture of ratio 5 ∶ 3
⇒ 30/(12 + y) = 5/3
⇒ 90 = 60 + 5y
⇒ 5y = 30
⇒ y = 30/5 = 6 kg
∴ The ratio of mixture can be changed to 5 ∶ 3 by adding 6 kg of gram flour
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A bag contained a mixture of wheat flour and gram flour in the ratio 5...
Let the quantity of wheat flour and gram flour in the bag be ‘5x’ kg and ‘2x’ kg
By adding 3 kg of wheat flour, the ratio becomes 11 ∶ 4
⇒ (5x + 3)/2x = 11/4
⇒ 20x + 12 = 22x
⇒ 2x = 12
⇒ x = 12/2 = 6 kg
⇒ Quantity of wheat flour in bag = 5x = 5 × 6 = 30 kg
⇒ Quantity of gram flour in bag = 2x = 2 × 6 = 12 kg
Now,
Let ‘y’ kg of gram flour be added to obtain a mixture of ratio 5 ∶ 3
⇒ 30/(12 + y) = 5/3
⇒ 90 = 60 + 5y
⇒ 5y = 30
⇒ y = 30/5 = 6 kg
∴ The ratio of mixture can be changed to 5 ∶ 3 by adding 6 kg of gram flour
A bag contained a mixture of wheat flour and gram flour in the ratio 5...
Given information:
- The bag initially contains a mixture of wheat flour and gram flour in the ratio 5:2.
- The ratio of the mixture can be changed to 11:4 by adding 3 kg of wheat flour.
Calculating the initial quantities:
Let's assume the bag initially contains 5x kg of wheat flour and 2x kg of gram flour.
Therefore, the total weight of the mixture is 5x + 2x = 7x kg.
Calculating the new quantities after adding wheat flour:
When 3 kg of wheat flour is added, the new ratio becomes 11:4.
So, the new ratio can be represented as (5x + 3):(2x) = 11:4.
Solving for x:
Using the concept of cross multiplication, we can write:
(5x + 3)/(2x) = 11/4
Cross multiplying, we get:
4(5x + 3) = 11(2x)
20x + 12 = 22x
Simplifying, we get:
2x = 12
x = 6
Calculating the initial quantities:
The initial quantity of wheat flour = 5x = 5(6) = 30 kg
The initial quantity of gram flour = 2x = 2(6) = 12 kg
Calculating the quantity of gram flour to be added:
To change the ratio to 5:3, we need to add some gram flour to the mixture.
Let's assume we need to add y kg of gram flour.
The new ratio can be represented as (30 + 3):(12 + y) = 5:3.
Solving for y:
Using the concept of cross multiplication, we can write:
(30 + 3)/(12 + y) = 5/3
Cross multiplying, we get:
3(30 + 3) = 5(12 + y)
90 + 9 = 60 + 5y
5y = 99 - 60
5y = 39
y = 39/5
y = 7.8
Approximating to the nearest integer, we get:
y = 8
Therefore, in order to change the ratio of the mixture to 5:3, we need to add 8 kg of gram flour.
Hence, the correct answer is option D) 8 kg.