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A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A potential difference of 4.0 V is applied across it for 120s. If the resistor is thermally insulated, what is the final rise in temperature? A. 8.0 x 10-4 K B. 3.2 x 10-3 K C. 9.6 x 10-2 K D. 0.38 K E. 9.6 K?
Most Upvoted Answer
A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A ...
Solution:
Given:
Resistance of the resistor, R = 1.0 kΩ
Thermal capacity of the resistor, C = 5.0 JK-1
Potential difference applied across the resistor, V = 4.0 V
Time for which the potential difference is applied, t = 120 s
The resistor is thermally insulated.
To find:
The final rise in temperature of the resistor.
Formula used:
The amount of heat generated, Q = V²/R
The amount of heat generated, Q = mCΔT
Where,
m - mass of the resistor
C - specific heat capacity of the resistor
ΔT - change in temperature of the resistor
Calculation:
The amount of heat generated in the resistor, Q = V²/R
Q = (4.0)²/(1.0 × 10³) = 1.6 × 10⁻³ J
The amount of heat generated can also be calculated as:
Q = mCΔT
ΔT = Q/mC
As the mass of the resistor is not given, we cannot directly use this formula.
But, we can relate the thermal capacity to the mass using the following formula:
C = mc
Where,
c - specific heat capacity of the resistor
Using this formula, we get:
m = C/c = 5.0/(1.0 × 10³) = 5.0 × 10⁻³ kg
Now, using the formula, Q = mCΔT
ΔT = Q/mC
ΔT = (1.6 × 10⁻³)/(5.0 × 10⁻³ × 1.0)
ΔT = 0.32 K
Therefore, the final rise in temperature of the resistor is 0.32 K.
Answer:
Option B: 3.2 x 10⁻³ K.
Given:
Resistance of the resistor, R = 1.0 kΩ
Thermal capacity of the resistor, C = 5.0 JK-1
Potential difference applied across the resistor, V = 4.0 V
Time for which the potential difference is applied, t = 120 s
The resistor is thermally insulated.
To find:
The final rise in temperature of the resistor.
Formula used:
The amount of heat generated, Q = V²/R
The amount of heat generated, Q = mCΔT
Where,
m - mass of the resistor
C - specific heat capacity of the resistor
ΔT - change in temperature of the resistor
Calculation:
The amount of heat generated in the resistor, Q = V²/R
Q = (4.0)²/(1.0 × 10³) = 1.6 × 10⁻³ J
The amount of heat generated can also be calculated as:
Q = mCΔT
ΔT = Q/mC
As the mass of the resistor is not given, we cannot directly use this formula.
But, we can relate the thermal capacity to the mass using the following formula:
C = mc
Where,
c - specific heat capacity of the resistor
Using this formula, we get:
m = C/c = 5.0/(1.0 × 10³) = 5.0 × 10⁻³ kg
Now, using the formula, Q = mCΔT
ΔT = Q/mC
ΔT = (1.6 × 10⁻³)/(5.0 × 10⁻³ × 1.0)
ΔT = 0.32 K
Therefore, the final rise in temperature of the resistor is 0.32 K.
Answer:
Option B: 3.2 x 10⁻³ K.
Community Answer
A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A ...
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A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A potential difference of 4.0 V is applied across it for 120s. If the resistor is thermally insulated, what is the final rise in temperature? A. 8.0 x 10-4 K B. 3.2 x 10-3 K C. 9.6 x 10-2 K D. 0.38 K E. 9.6 K?
Question Description
A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A potential difference of 4.0 V is applied across it for 120s. If the resistor is thermally insulated, what is the final rise in temperature? A. 8.0 x 10-4 K B. 3.2 x 10-3 K C. 9.6 x 10-2 K D. 0.38 K E. 9.6 K? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A potential difference of 4.0 V is applied across it for 120s. If the resistor is thermally insulated, what is the final rise in temperature? A. 8.0 x 10-4 K B. 3.2 x 10-3 K C. 9.6 x 10-2 K D. 0.38 K E. 9.6 K? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A potential difference of 4.0 V is applied across it for 120s. If the resistor is thermally insulated, what is the final rise in temperature? A. 8.0 x 10-4 K B. 3.2 x 10-3 K C. 9.6 x 10-2 K D. 0.38 K E. 9.6 K?.
A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A potential difference of 4.0 V is applied across it for 120s. If the resistor is thermally insulated, what is the final rise in temperature? A. 8.0 x 10-4 K B. 3.2 x 10-3 K C. 9.6 x 10-2 K D. 0.38 K E. 9.6 K? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A potential difference of 4.0 V is applied across it for 120s. If the resistor is thermally insulated, what is the final rise in temperature? A. 8.0 x 10-4 K B. 3.2 x 10-3 K C. 9.6 x 10-2 K D. 0.38 K E. 9.6 K? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A potential difference of 4.0 V is applied across it for 120s. If the resistor is thermally insulated, what is the final rise in temperature? A. 8.0 x 10-4 K B. 3.2 x 10-3 K C. 9.6 x 10-2 K D. 0.38 K E. 9.6 K?.
Solutions for A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A potential difference of 4.0 V is applied across it for 120s. If the resistor is thermally insulated, what is the final rise in temperature? A. 8.0 x 10-4 K B. 3.2 x 10-3 K C. 9.6 x 10-2 K D. 0.38 K E. 9.6 K? in English & in Hindi are available as part of our courses for NEET.
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A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A potential difference of 4.0 V is applied across it for 120s. If the resistor is thermally insulated, what is the final rise in temperature? A. 8.0 x 10-4 K B. 3.2 x 10-3 K C. 9.6 x 10-2 K D. 0.38 K E. 9.6 K?, a detailed solution for A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A potential difference of 4.0 V is applied across it for 120s. If the resistor is thermally insulated, what is the final rise in temperature? A. 8.0 x 10-4 K B. 3.2 x 10-3 K C. 9.6 x 10-2 K D. 0.38 K E. 9.6 K? has been provided alongside types of A resistor of resistance 1.0 kΩ has a thermal capacity of 5.0 JK-1. A potential difference of 4.0 V is applied across it for 120s. If the resistor is thermally insulated, what is the final rise in temperature? A. 8.0 x 10-4 K B. 3.2 x 10-3 K C. 9.6 x 10-2 K D. 0.38 K E. 9.6 K? theory, EduRev gives you an
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