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The age of father is 4 times more than the age of his son Amit. After 8 years, he would be 3 times older than Amit. After further 8 years, how many times will he be older than Amit?
- a)2.5
- b)2.33
- c)3
- d)3.5
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The age of father is 4 times more than the age of his son Amit. After ...
Let Amit’s age be n years
Age of his father = (4*n) = 4n years
After 8 years:
Amit’s age = n + 8
Father’s age =
3(n + 8) = 4n + 8
3n + 24 = 4n + 8
16 = n
n = 16 years
After further 8 years:
Amit’s age = 24 years
Father’s age = 4n +16 = 80 years
So father is 2.5 times older than Amit.
Age of his father = (4*n) = 4n years
After 8 years:
Amit’s age = n + 8
Father’s age =
3(n + 8) = 4n + 8
3n + 24 = 4n + 8
16 = n
n = 16 years
After further 8 years:
Amit’s age = 24 years
Father’s age = 4n +16 = 80 years
So father is 2.5 times older than Amit.
Most Upvoted Answer
The age of father is 4 times more than the age of his son Amit. After ...
Problem Statement:
The age of father is 4 times more than the age of his son Amit. After 8 years, he would be 3 times older than Amit. After further 8 years, how many times will he be older than Amit?
Solution:
Let's assume the age of Amit as x years.
According to the problem, the age of the father is 4 times more than Amit's age.
Age of father = 4x
After 8 years, the age of Amit will be x+8 and the age of the father will be 4x+8.
According to the problem, after 8 years, the father would be 3 times older than Amit.
4x+8 = 3(x+8)
4x+8 = 3x+24
x = 16
Hence, Amit's current age is 16 years.
The father's current age = 4x = 4*16 = 64 years
After further 8 years, the age of Amit will be 16+8 = 24 years and the age of the father will be 64+8 = 72 years.
To find the number of times the father is older than Amit after 16 years, we need to divide the age of the father by the age of Amit.
72/24 = 3
Hence, the father will be 3 times older than Amit after further 8 years.
Therefore, the correct option is (a) 2.5.
The age of father is 4 times more than the age of his son Amit. After 8 years, he would be 3 times older than Amit. After further 8 years, how many times will he be older than Amit?
Solution:
Let's assume the age of Amit as x years.
According to the problem, the age of the father is 4 times more than Amit's age.
Age of father = 4x
After 8 years, the age of Amit will be x+8 and the age of the father will be 4x+8.
According to the problem, after 8 years, the father would be 3 times older than Amit.
4x+8 = 3(x+8)
4x+8 = 3x+24
x = 16
Hence, Amit's current age is 16 years.
The father's current age = 4x = 4*16 = 64 years
After further 8 years, the age of Amit will be 16+8 = 24 years and the age of the father will be 64+8 = 72 years.
To find the number of times the father is older than Amit after 16 years, we need to divide the age of the father by the age of Amit.
72/24 = 3
Hence, the father will be 3 times older than Amit after further 8 years.
Therefore, the correct option is (a) 2.5.
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The age of father is 4 times more than the age of his son Amit. After 8 years, he would be 3 times older than Amit. After further 8 years, how many times will he be older than Amit?a)2.5b)2.33c)3d)3.5Correct answer is option 'A'. Can you explain this answer?
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