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A series LCR circuit is connected to an AC voltage source. When L is removed from the circuit, the phase difference between current and voltage is π / 3 . If instead C is removed from the circuit, the phase difference is again π / 3 between current and voltage. The power factor of the circuit is :
- a)1.0
- b)–1.0
- c)zero
- d)0.5
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A series LCR circuit is connected to an AC voltage source. When L is r...
When inductor alone is removed,
XC = R √3
When capacitor alone is removed,
Thus, for the original circuit,
X = R √3 = X
= XL = XC ⇒ (Z = R)
power factor =
XC = R √3
When capacitor alone is removed,
Thus, for the original circuit,
X = R √3 = X
= XL = XC ⇒ (Z = R)
power factor =
Most Upvoted Answer
A series LCR circuit is connected to an AC voltage source. When L is r...
90 degrees.
Explanation:
In a series LCR circuit, the current and voltage are out of phase because of the presence of inductance and capacitance. The phase angle between current and voltage is given by:
tan Φ = (XL - XC)/R
where XL is the inductive reactance, XC is the capacitive reactance, and R is the resistance of the circuit.
When L is removed from the circuit, XL becomes zero and the phase angle reduces to:
tan Φ = -XC/R
Since XC is inversely proportional to frequency, its value increases as the frequency decreases. Therefore, at low frequencies, XC can be much larger than R, and the phase angle can approach -90 degrees.
Hence, when L is removed from the circuit, the capacitive reactance dominates, and the phase difference between current and voltage becomes close to 90 degrees.
Explanation:
In a series LCR circuit, the current and voltage are out of phase because of the presence of inductance and capacitance. The phase angle between current and voltage is given by:
tan Φ = (XL - XC)/R
where XL is the inductive reactance, XC is the capacitive reactance, and R is the resistance of the circuit.
When L is removed from the circuit, XL becomes zero and the phase angle reduces to:
tan Φ = -XC/R
Since XC is inversely proportional to frequency, its value increases as the frequency decreases. Therefore, at low frequencies, XC can be much larger than R, and the phase angle can approach -90 degrees.
Hence, when L is removed from the circuit, the capacitive reactance dominates, and the phase difference between current and voltage becomes close to 90 degrees.
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A series LCR circuit is connected to an AC voltage source. When L is removed from the circuit, the phase difference between current and voltage isπ / 3. If instead C is removed from the circuit, the phase difference is againπ / 3between current and voltage. The power factor of the circuit is :a)1.0b)–1.0c)zerod)0.5Correct answer is option 'A'. Can you explain this answer?
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A series LCR circuit is connected to an AC voltage source. When L is removed from the circuit, the phase difference between current and voltage isπ / 3. If instead C is removed from the circuit, the phase difference is againπ / 3between current and voltage. The power factor of the circuit is :a)1.0b)–1.0c)zerod)0.5Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A series LCR circuit is connected to an AC voltage source. When L is removed from the circuit, the phase difference between current and voltage isπ / 3. If instead C is removed from the circuit, the phase difference is againπ / 3between current and voltage. The power factor of the circuit is :a)1.0b)–1.0c)zerod)0.5Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A series LCR circuit is connected to an AC voltage source. When L is removed from the circuit, the phase difference between current and voltage isπ / 3. If instead C is removed from the circuit, the phase difference is againπ / 3between current and voltage. The power factor of the circuit is :a)1.0b)–1.0c)zerod)0.5Correct answer is option 'A'. Can you explain this answer?.
A series LCR circuit is connected to an AC voltage source. When L is removed from the circuit, the phase difference between current and voltage isπ / 3. If instead C is removed from the circuit, the phase difference is againπ / 3between current and voltage. The power factor of the circuit is :a)1.0b)–1.0c)zerod)0.5Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A series LCR circuit is connected to an AC voltage source. When L is removed from the circuit, the phase difference between current and voltage isπ / 3. If instead C is removed from the circuit, the phase difference is againπ / 3between current and voltage. The power factor of the circuit is :a)1.0b)–1.0c)zerod)0.5Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A series LCR circuit is connected to an AC voltage source. When L is removed from the circuit, the phase difference between current and voltage isπ / 3. If instead C is removed from the circuit, the phase difference is againπ / 3between current and voltage. The power factor of the circuit is :a)1.0b)–1.0c)zerod)0.5Correct answer is option 'A'. Can you explain this answer?.
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