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A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 ohm is connected in the collector circuit and the voltage drop across it is 0.8v.If the current amplification factor is 0.96 and the input resistance of the resistance circuit is 192 ohm, the voltage gain and the power gain of the amplifier will respectively be a]4, 4 b]4, 3.69 c]4, 3.84 d]3.69, 3.84?
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A npn transistor is connected in common emitter configuration in a giv...
Given information:
- NPN transistor in common emitter configuration
- Load resistance = 800 ohm, voltage drop across it = 0.8V
- Current amplification factor = 0.96
- Input resistance of the resistance circuit = 192 ohm
Calculating voltage gain:
- Voltage gain = (output voltage / input voltage)
- Output voltage = voltage drop across load resistance = 0.8V
- Input voltage = (input current * input resistance) = ((output current / current amplification factor) * input resistance)
- Output current = (load voltage / load resistance) = (0.8V / 800 ohm) = 1mA
- Input current = output current / current amplification factor = 1mA / 0.96 = 1.042mA
- Input voltage = (1.042mA * 192 ohm) = 0.199V
- Voltage gain = (0.8V / 0.199V) = 4.02
Calculating power gain:
- Power gain = (output power / input power)
- Output power = (load voltage * output current) = (0.8V * 1mA) = 0.8mW
- Input power = (input voltage * input current) = (0.199V * 1.042mA) = 0.207mW
- Power gain = (0.8mW / 0.207mW) = 3.86
Therefore, the voltage gain and power gain of the amplifier will be 4.02 and 3.86 respectively. The answer is option (c) 4, 3.84.
- NPN transistor in common emitter configuration
- Load resistance = 800 ohm, voltage drop across it = 0.8V
- Current amplification factor = 0.96
- Input resistance of the resistance circuit = 192 ohm
Calculating voltage gain:
- Voltage gain = (output voltage / input voltage)
- Output voltage = voltage drop across load resistance = 0.8V
- Input voltage = (input current * input resistance) = ((output current / current amplification factor) * input resistance)
- Output current = (load voltage / load resistance) = (0.8V / 800 ohm) = 1mA
- Input current = output current / current amplification factor = 1mA / 0.96 = 1.042mA
- Input voltage = (1.042mA * 192 ohm) = 0.199V
- Voltage gain = (0.8V / 0.199V) = 4.02
Calculating power gain:
- Power gain = (output power / input power)
- Output power = (load voltage * output current) = (0.8V * 1mA) = 0.8mW
- Input power = (input voltage * input current) = (0.199V * 1.042mA) = 0.207mW
- Power gain = (0.8mW / 0.207mW) = 3.86
Therefore, the voltage gain and power gain of the amplifier will be 4.02 and 3.86 respectively. The answer is option (c) 4, 3.84.
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A npn transistor is connected in common emitter configuration in a giv...
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A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 ohm is connected in the collector circuit and the voltage drop across it is 0.8v.If the current amplification factor is 0.96 and the input resistance of the resistance circuit is 192 ohm, the voltage gain and the power gain of the amplifier will respectively be a]4, 4 b]4, 3.69 c]4, 3.84 d]3.69, 3.84?
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A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 ohm is connected in the collector circuit and the voltage drop across it is 0.8v.If the current amplification factor is 0.96 and the input resistance of the resistance circuit is 192 ohm, the voltage gain and the power gain of the amplifier will respectively be a]4, 4 b]4, 3.69 c]4, 3.84 d]3.69, 3.84? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 ohm is connected in the collector circuit and the voltage drop across it is 0.8v.If the current amplification factor is 0.96 and the input resistance of the resistance circuit is 192 ohm, the voltage gain and the power gain of the amplifier will respectively be a]4, 4 b]4, 3.69 c]4, 3.84 d]3.69, 3.84? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 ohm is connected in the collector circuit and the voltage drop across it is 0.8v.If the current amplification factor is 0.96 and the input resistance of the resistance circuit is 192 ohm, the voltage gain and the power gain of the amplifier will respectively be a]4, 4 b]4, 3.69 c]4, 3.84 d]3.69, 3.84?.
A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 ohm is connected in the collector circuit and the voltage drop across it is 0.8v.If the current amplification factor is 0.96 and the input resistance of the resistance circuit is 192 ohm, the voltage gain and the power gain of the amplifier will respectively be a]4, 4 b]4, 3.69 c]4, 3.84 d]3.69, 3.84? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 ohm is connected in the collector circuit and the voltage drop across it is 0.8v.If the current amplification factor is 0.96 and the input resistance of the resistance circuit is 192 ohm, the voltage gain and the power gain of the amplifier will respectively be a]4, 4 b]4, 3.69 c]4, 3.84 d]3.69, 3.84? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 ohm is connected in the collector circuit and the voltage drop across it is 0.8v.If the current amplification factor is 0.96 and the input resistance of the resistance circuit is 192 ohm, the voltage gain and the power gain of the amplifier will respectively be a]4, 4 b]4, 3.69 c]4, 3.84 d]3.69, 3.84?.
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A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 ohm is connected in the collector circuit and the voltage drop across it is 0.8v.If the current amplification factor is 0.96 and the input resistance of the resistance circuit is 192 ohm, the voltage gain and the power gain of the amplifier will respectively be a]4, 4 b]4, 3.69 c]4, 3.84 d]3.69, 3.84?, a detailed solution for A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 ohm is connected in the collector circuit and the voltage drop across it is 0.8v.If the current amplification factor is 0.96 and the input resistance of the resistance circuit is 192 ohm, the voltage gain and the power gain of the amplifier will respectively be a]4, 4 b]4, 3.69 c]4, 3.84 d]3.69, 3.84? has been provided alongside types of A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 ohm is connected in the collector circuit and the voltage drop across it is 0.8v.If the current amplification factor is 0.96 and the input resistance of the resistance circuit is 192 ohm, the voltage gain and the power gain of the amplifier will respectively be a]4, 4 b]4, 3.69 c]4, 3.84 d]3.69, 3.84? theory, EduRev gives you an
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