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The current gain beta of a transistor is 50. The input resistance of the transistor, when used in the common emitter configuration is 1kilo ohm. The peak value of the collector a.c. current, for an alternating peak input voltage of 0.01V is :- A- 100 micro A B- 250 micro A C- 500 micro A D- 800 micro A?
Ans is C but can anyone explain it ?
Ans is C but can anyone explain it ?
Most Upvoted Answer
The current gain beta of a transistor is 50. The input resistance of t...
The given problem involves calculating the peak value of the collector a.c. current for an alternating peak input voltage of 0.01V. We are given the current gain beta of the transistor as 50 and the input resistance of the transistor in the common emitter configuration as 1 kilo ohm.
To solve this problem, we can use the following steps:
1. Identify the relevant formulas:
- The current gain beta (β) of a transistor is defined as the ratio of the collector current (Ic) to the base current (Ib): β = Ic/Ib.
- The input resistance (Rin) of a transistor in the common emitter configuration can be calculated using the formula: Rin = β * (re + RB), where re is the emitter resistance and RB is the base resistance.
2. Calculate the emitter resistance (re):
- The emitter resistance (re) can be approximated as the reciprocal of the transconductance (gm): re ≈ 1/gm.
- The transconductance (gm) can be calculated using the formula: gm = Ic/Vt, where Vt is the thermal voltage (approximately 26 mV at room temperature).
3. Calculate the base resistance (RB):
- The base resistance (RB) can be calculated as the parallel combination of the base-emitter junction resistance (rπ) and the base spreading resistance (RB'): RB = rπ || RB'.
- The base-emitter junction resistance (rπ) can be approximated as the reciprocal of the transconductance (gm): rπ ≈ 1/gm.
- The base spreading resistance (RB') is negligible for most transistors.
4. Substitute the known values into the input resistance formula and solve for Rin:
- Rin = β * (re + RB)
- Substitute the values of β, re, and RB to calculate Rin.
5. Calculate the peak value of the collector a.c. current (Ic):
- The peak value of the collector a.c. current (Ic) can be calculated using the formula: Ic = β * Ib.
- The base current (Ib) can be calculated using Ohm's law: Ib = Vin / Rin.
- Substitute the known values of Vin and Rin to calculate Ib, and then substitute Ib and β to calculate Ic.
By following these steps, we can calculate the peak value of the collector a.c. current. In this case, the answer is 500 micro A (option C).
To solve this problem, we can use the following steps:
1. Identify the relevant formulas:
- The current gain beta (β) of a transistor is defined as the ratio of the collector current (Ic) to the base current (Ib): β = Ic/Ib.
- The input resistance (Rin) of a transistor in the common emitter configuration can be calculated using the formula: Rin = β * (re + RB), where re is the emitter resistance and RB is the base resistance.
2. Calculate the emitter resistance (re):
- The emitter resistance (re) can be approximated as the reciprocal of the transconductance (gm): re ≈ 1/gm.
- The transconductance (gm) can be calculated using the formula: gm = Ic/Vt, where Vt is the thermal voltage (approximately 26 mV at room temperature).
3. Calculate the base resistance (RB):
- The base resistance (RB) can be calculated as the parallel combination of the base-emitter junction resistance (rπ) and the base spreading resistance (RB'): RB = rπ || RB'.
- The base-emitter junction resistance (rπ) can be approximated as the reciprocal of the transconductance (gm): rπ ≈ 1/gm.
- The base spreading resistance (RB') is negligible for most transistors.
4. Substitute the known values into the input resistance formula and solve for Rin:
- Rin = β * (re + RB)
- Substitute the values of β, re, and RB to calculate Rin.
5. Calculate the peak value of the collector a.c. current (Ic):
- The peak value of the collector a.c. current (Ic) can be calculated using the formula: Ic = β * Ib.
- The base current (Ib) can be calculated using Ohm's law: Ib = Vin / Rin.
- Substitute the known values of Vin and Rin to calculate Ib, and then substitute Ib and β to calculate Ic.
By following these steps, we can calculate the peak value of the collector a.c. current. In this case, the answer is 500 micro A (option C).
Community Answer
The current gain beta of a transistor is 50. The input resistance of t...
Input current = input voltage/input resistance
0.01/1000 =10^-5
current gain= collector current/base current
50 *10^-5 =500 micro
0.01/1000 =10^-5
current gain= collector current/base current
50 *10^-5 =500 micro
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The current gain beta of a transistor is 50. The input resistance of the transistor, when used in the common emitter configuration is 1kilo ohm. The peak value of the collector a.c. current, for an alternating peak input voltage of 0.01V is :- A- 100 micro A B- 250 micro A C- 500 micro A D- 800 micro A?Ans is C but can anyone explain it ?
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The current gain beta of a transistor is 50. The input resistance of the transistor, when used in the common emitter configuration is 1kilo ohm. The peak value of the collector a.c. current, for an alternating peak input voltage of 0.01V is :- A- 100 micro A B- 250 micro A C- 500 micro A D- 800 micro A?Ans is C but can anyone explain it ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The current gain beta of a transistor is 50. The input resistance of the transistor, when used in the common emitter configuration is 1kilo ohm. The peak value of the collector a.c. current, for an alternating peak input voltage of 0.01V is :- A- 100 micro A B- 250 micro A C- 500 micro A D- 800 micro A?Ans is C but can anyone explain it ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The current gain beta of a transistor is 50. The input resistance of the transistor, when used in the common emitter configuration is 1kilo ohm. The peak value of the collector a.c. current, for an alternating peak input voltage of 0.01V is :- A- 100 micro A B- 250 micro A C- 500 micro A D- 800 micro A?Ans is C but can anyone explain it ?.
The current gain beta of a transistor is 50. The input resistance of the transistor, when used in the common emitter configuration is 1kilo ohm. The peak value of the collector a.c. current, for an alternating peak input voltage of 0.01V is :- A- 100 micro A B- 250 micro A C- 500 micro A D- 800 micro A?Ans is C but can anyone explain it ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The current gain beta of a transistor is 50. The input resistance of the transistor, when used in the common emitter configuration is 1kilo ohm. The peak value of the collector a.c. current, for an alternating peak input voltage of 0.01V is :- A- 100 micro A B- 250 micro A C- 500 micro A D- 800 micro A?Ans is C but can anyone explain it ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The current gain beta of a transistor is 50. The input resistance of the transistor, when used in the common emitter configuration is 1kilo ohm. The peak value of the collector a.c. current, for an alternating peak input voltage of 0.01V is :- A- 100 micro A B- 250 micro A C- 500 micro A D- 800 micro A?Ans is C but can anyone explain it ?.
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The current gain beta of a transistor is 50. The input resistance of the transistor, when used in the common emitter configuration is 1kilo ohm. The peak value of the collector a.c. current, for an alternating peak input voltage of 0.01V is :- A- 100 micro A B- 250 micro A C- 500 micro A D- 800 micro A?Ans is C but can anyone explain it ?, a detailed solution for The current gain beta of a transistor is 50. The input resistance of the transistor, when used in the common emitter configuration is 1kilo ohm. The peak value of the collector a.c. current, for an alternating peak input voltage of 0.01V is :- A- 100 micro A B- 250 micro A C- 500 micro A D- 800 micro A?Ans is C but can anyone explain it ? has been provided alongside types of The current gain beta of a transistor is 50. The input resistance of the transistor, when used in the common emitter configuration is 1kilo ohm. The peak value of the collector a.c. current, for an alternating peak input voltage of 0.01V is :- A- 100 micro A B- 250 micro A C- 500 micro A D- 800 micro A?Ans is C but can anyone explain it ? theory, EduRev gives you an
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