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The input resistance of a silicon transistor is 100 W. Base current is changed by 40 μA which results in a change in collector current by 2 mA.
This transistor is used as a common emitter amplifier with a load resistance of 4 kΩ. The power gain of the amplifier is :
  • a)
    105
  • b)
    103
  • c)
    106
  • d)
    102
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The input resistance of a silicon transistor is 100 W. Base current i...
Calculation of Power Gain:
1. Input Resistance (Rin): Given input resistance of the transistor is 100 Ω.
2. Change in Base Current (ΔIB): 40 μA.
3. Change in Collector Current (ΔIC): 2 mA.
4. Gain in Collector Current (β): β = ΔIC / ΔIB = 2 mA / 40 μA = 50.
5. Output Resistance (Rout): Assuming it is very large compared to the load resistance.
6. Voltage Gain (Av): Av = -β * Rout / Rin = -50 * 4000 / 100 = -2000.
7. Power Gain: Power Gain = (Voltage Gain)2 = (-2000)2 = 4000000 = 4000.
8. Power Gain in dB: Power Gain(dB) = 10 * log(Power Gain) = 10 * log(4000) = 36 dB.
Therefore, the power gain of the amplifier is approximately 105 (rounded off to the nearest whole number).
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The input resistance of a silicon transistor is 100 W. Base current is changed by 40 μA which results in a change in collector current by 2 mA.This transistor is used as a common emitter amplifier with a load resistance of 4 kΩ. The power gain of the amplifier is :a)105b)103c)106d)102Correct answer is option 'A'. Can you explain this answer?
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