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In Young's double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes :
- a)four times
- b)one-fourth
- c)double
- d)half
Correct answer is option 'A'. Can you explain this answer?
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In Youngs double slit experiment, if the separation between coherent s...
Fringe width in YDSE is given by
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In Youngs double slit experiment, if the separation between coherent s...
Explanation:
The Young's double-slit experiment is a classic experiment that demonstrates the wave nature of light. In this experiment, light passes through two narrow slits and forms an interference pattern on a screen. The pattern consists of alternating bright and dark fringes.
Given:
- The separation between coherent sources (slits) is halved.
- The distance of the screen from the coherent sources is doubled.
Effect on Fringe Width:
- The fringe width is the distance between two adjacent bright or dark fringes.
- It is given by the equation: w = λL / d
- where w is the fringe width, λ is the wavelength of light, L is the distance of the screen from the slits, and d is the separation between the slits.
- Let's consider the initial values: d1 (original separation between slits) and L1 (original distance of the screen from slits).
- After halving the separation between slits, the new separation becomes d2 = d1/2.
- After doubling the distance of the screen, the new distance becomes L2 = 2L1.
Calculating the Ratio:
- Let's calculate the ratio of the new fringe width (w2) to the initial fringe width (w1).
- w2 = λL2 / d2
= λ(2L1) / (d1/2)
= 4(λL1 / d1)
= 4w1
Conclusion:
- The ratio of the new fringe width (w2) to the initial fringe width (w1) is 4.
- This means that the new fringe width is four times the initial fringe width.
- Therefore, the correct answer is option 'A': four times.
The Young's double-slit experiment is a classic experiment that demonstrates the wave nature of light. In this experiment, light passes through two narrow slits and forms an interference pattern on a screen. The pattern consists of alternating bright and dark fringes.
Given:
- The separation between coherent sources (slits) is halved.
- The distance of the screen from the coherent sources is doubled.
Effect on Fringe Width:
- The fringe width is the distance between two adjacent bright or dark fringes.
- It is given by the equation: w = λL / d
- where w is the fringe width, λ is the wavelength of light, L is the distance of the screen from the slits, and d is the separation between the slits.
- Let's consider the initial values: d1 (original separation between slits) and L1 (original distance of the screen from slits).
- After halving the separation between slits, the new separation becomes d2 = d1/2.
- After doubling the distance of the screen, the new distance becomes L2 = 2L1.
Calculating the Ratio:
- Let's calculate the ratio of the new fringe width (w2) to the initial fringe width (w1).
- w2 = λL2 / d2
= λ(2L1) / (d1/2)
= 4(λL1 / d1)
= 4w1
Conclusion:
- The ratio of the new fringe width (w2) to the initial fringe width (w1) is 4.
- This means that the new fringe width is four times the initial fringe width.
- Therefore, the correct answer is option 'A': four times.
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In Youngs double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes :a)four timesb)one-fourthc)doubled)halfCorrect answer is option 'A'. Can you explain this answer?
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