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In Young's double slit experiment, if the distance between the slits and the screen is doubled and the separation between the slits is reduced to half, the fringe width
- a)is doubled
- b)becomes four times
- c)is halved
- d)remains unchanged
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
In Young's double slit experiment, if the distance between the slits ...
Explanation:
Young's double-slit experiment is an experiment that demonstrates the wave nature of light. The interference pattern is formed when light passes through two narrow slits and falls on a screen placed at a certain distance from the slits. The pattern consists of bright and dark fringes.
Fringe Width:
The fringe width is defined as the distance between two consecutive bright or dark fringes. It is given by the formula:
w = λD/d
where λ is the wavelength of light, D is the distance between the slits and the screen, and d is the distance between the slits.
Effect of Changing Distance and Separation on Fringe Width:
- Doubling the distance between the slits and the screen:
If the distance between the slits and the screen is doubled, the fringe width will be halved. This is because the fringe width is inversely proportional to the distance between the slits and the screen. Therefore, the new fringe width will be:
w' = λ(2D)/d = 2λD/d
- Reducing the separation between the slits to half:
If the separation between the slits is reduced to half, the fringe width will be doubled. This is because the fringe width is directly proportional to the separation between the slits. Therefore, the new fringe width will be:
w'' = λD/(d/2) = 2λD/d
Combining the two effects:
If both effects are combined, i.e., the distance between the slits and the screen is doubled and the separation between the slits is reduced to half, then:
w''' = λ(2D)/(d/2) = 4λD/d
Therefore, the new fringe width will be four times the original fringe width.
Conclusion:
Thus, if the distance between the slits and the screen is doubled and the separation between the slits is reduced to half, the fringe width becomes four times.
Young's double-slit experiment is an experiment that demonstrates the wave nature of light. The interference pattern is formed when light passes through two narrow slits and falls on a screen placed at a certain distance from the slits. The pattern consists of bright and dark fringes.
Fringe Width:
The fringe width is defined as the distance between two consecutive bright or dark fringes. It is given by the formula:
w = λD/d
where λ is the wavelength of light, D is the distance between the slits and the screen, and d is the distance between the slits.
Effect of Changing Distance and Separation on Fringe Width:
- Doubling the distance between the slits and the screen:
If the distance between the slits and the screen is doubled, the fringe width will be halved. This is because the fringe width is inversely proportional to the distance between the slits and the screen. Therefore, the new fringe width will be:
w' = λ(2D)/d = 2λD/d
- Reducing the separation between the slits to half:
If the separation between the slits is reduced to half, the fringe width will be doubled. This is because the fringe width is directly proportional to the separation between the slits. Therefore, the new fringe width will be:
w'' = λD/(d/2) = 2λD/d
Combining the two effects:
If both effects are combined, i.e., the distance between the slits and the screen is doubled and the separation between the slits is reduced to half, then:
w''' = λ(2D)/(d/2) = 4λD/d
Therefore, the new fringe width will be four times the original fringe width.
Conclusion:
Thus, if the distance between the slits and the screen is doubled and the separation between the slits is reduced to half, the fringe width becomes four times.
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Community Answer
In Young's double slit experiment, if the distance between the slits ...
Since β = λD/d, if D is doubled and d is halved, the fringe width β will become four times. Hence the correct choice is (2).
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In Young's double slit experiment, if the distance between the slits and the screen is doubled and the separation between the slits is reduced to half, the fringe widtha)is doubledb)becomes four timesc)is halvedd)remains unchangedCorrect answer is option 'B'. Can you explain this answer?
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