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What shd be the pH of solⁿ obtained by mixing 100ml of 0.1N HCl & 9.9ml of 1.0N NaOH solⁿ?? .ans is 3.05.plss expln
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What shd be the pH of solⁿ obtained by mixing 100ml of 0.1N HCl & 9.9m...
NV of acid is more than NV of base.. so soln is acidic nd formula will be N1V1 acid -- N2V2 base = Nsoln ×V total . now, put value .. 10-- 9.9= N × 109.9 N = 0.1/109.9 N= 9×10^-4 almost.. tht means H plus ions( since soln is acidic) = 9× 10^-4. pH = 3.05
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What shd be the pH of solⁿ obtained by mixing 100ml of 0.1N HCl & 9.9m...
thanku bro :)
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What shd be the pH of solⁿ obtained by mixing 100ml of 0.1N HCl & 9.9ml of 1.0N NaOH solⁿ?? .ans is 3.05.plss expln
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