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what is the product of CH3-O-C2H5 on reacting with anhydrous HI and concentrated HI respectively ?(both r different reaction plzz tell the product)
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what is the product of CH3-O-C2H5 on reacting with anhydrous HI and co...
Reaction with Anhydrous HI:
The reaction of CH3-O-C2H5 (also known as ethyl methyl ether) with anhydrous hydrogen iodide (HI) results in the formation of ethanol and methyl iodide. This reaction is an example of nucleophilic substitution.
Mechanism:
1. Protonation: The first step involves the protonation of the ether oxygen atom by the strong acid, HI. The oxygen atom of the ether acts as a nucleophile and attacks the hydrogen ion, forming an oxonium ion.
2. Nucleophilic Substitution: In the next step, the nucleophilic oxygen atom attacks the carbon atom of the methyl group in the oxonium ion. This leads to the formation of a new carbon-oxygen bond and the breaking of the carbon-iodine bond.
3. Elimination: Finally, the iodide ion is protonated by another molecule of HI, resulting in the formation of methyl iodide, which is a volatile compound, and ethanol.
Overall Reaction:
CH3-O-C2H5 + HI → CH3-I + C2H5OH
Reaction with Concentrated HI:
The reaction of CH3-O-C2H5 with concentrated HI involves the cleavage of the carbon-oxygen bond, leading to the formation of ethyl iodide and methanol. This reaction is an example of hydrolysis.
Mechanism:
1. Protonation: Similar to the previous reaction, the first step involves the protonation of the ether oxygen atom by the acid. The oxygen atom of the ether acts as a nucleophile and attacks the hydrogen ion, forming an oxonium ion.
2. Cleavage: In the next step, the oxonium ion undergoes cleavage of the carbon-oxygen bond. This results in the formation of a carbocation and an alcohol molecule.
3. Nucleophilic Substitution: The carbocation intermediate is then attacked by the iodide ion, which acts as a nucleophile. This leads to the formation of ethyl iodide and regenerates the acid catalyst.
Overall Reaction:
CH3-O-C2H5 + HI → C2H5I + CH3OH
Summary:
In summary, when CH3-O-C2H5 reacts with anhydrous HI, ethanol and methyl iodide are formed through a nucleophilic substitution reaction. On the other hand, when it reacts with concentrated HI, ethyl iodide and methanol are formed through a hydrolysis reaction.
The reaction of CH3-O-C2H5 (also known as ethyl methyl ether) with anhydrous hydrogen iodide (HI) results in the formation of ethanol and methyl iodide. This reaction is an example of nucleophilic substitution.
Mechanism:
1. Protonation: The first step involves the protonation of the ether oxygen atom by the strong acid, HI. The oxygen atom of the ether acts as a nucleophile and attacks the hydrogen ion, forming an oxonium ion.
2. Nucleophilic Substitution: In the next step, the nucleophilic oxygen atom attacks the carbon atom of the methyl group in the oxonium ion. This leads to the formation of a new carbon-oxygen bond and the breaking of the carbon-iodine bond.
3. Elimination: Finally, the iodide ion is protonated by another molecule of HI, resulting in the formation of methyl iodide, which is a volatile compound, and ethanol.
Overall Reaction:
CH3-O-C2H5 + HI → CH3-I + C2H5OH
Reaction with Concentrated HI:
The reaction of CH3-O-C2H5 with concentrated HI involves the cleavage of the carbon-oxygen bond, leading to the formation of ethyl iodide and methanol. This reaction is an example of hydrolysis.
Mechanism:
1. Protonation: Similar to the previous reaction, the first step involves the protonation of the ether oxygen atom by the acid. The oxygen atom of the ether acts as a nucleophile and attacks the hydrogen ion, forming an oxonium ion.
2. Cleavage: In the next step, the oxonium ion undergoes cleavage of the carbon-oxygen bond. This results in the formation of a carbocation and an alcohol molecule.
3. Nucleophilic Substitution: The carbocation intermediate is then attacked by the iodide ion, which acts as a nucleophile. This leads to the formation of ethyl iodide and regenerates the acid catalyst.
Overall Reaction:
CH3-O-C2H5 + HI → C2H5I + CH3OH
Summary:
In summary, when CH3-O-C2H5 reacts with anhydrous HI, ethanol and methyl iodide are formed through a nucleophilic substitution reaction. On the other hand, when it reacts with concentrated HI, ethyl iodide and methanol are formed through a hydrolysis reaction.
Community Answer
what is the product of CH3-O-C2H5 on reacting with anhydrous HI and co...
conc HI se CH3 I + C-C-OH
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what is the product of CH3-O-C2H5 on reacting with anhydrous HI and concentrated HI respectively ?(both r different reaction plzz tell the product)
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