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Two identical spherical conducting bodies A and B carries charges 2C and 8C respectively.Now a -4C charge is added to both of them and then they are made in contact for some time.The number of electrons present in excess/deficient in them are 1)2.5×10^16 in excess 2)2.5×10^16 in deficient 3)6.25×10^18 in deficient 4)3.375×10^18in excess?
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Two identical spherical conducting bodies A and B carries charges 2C a...
**Given Information:**
- Two identical spherical conducting bodies A and B carry charges 2C and 8C respectively.
- A -4C charge is added to both bodies A and B.
- They are then made in contact for some time.

**Goal:**
To determine the number of excess or deficient electrons in bodies A and B after they are made in contact.

**Understanding the Problem:**
- Conducting bodies have the property of allowing charges to move freely.
- When two conductors are brought into contact, they tend to reach equilibrium by redistributing charges between them.
- The total charge remains conserved during this process.

**Solution:**

1. **Initial State:**
- Body A has a charge of 2C.
- Body B has a charge of 8C.
- Total charge before contact = 2C + 8C = 10C.

2. **Addition of -4C charge to A and B:**
- After adding -4C to both bodies, the charges become:
- Body A: 2C - 4C = -2C
- Body B: 8C - 4C = 4C
- Total charge before contact = -2C + 4C = 2C.

3. **Making Contact:**
- When bodies A and B are brought into contact, they redistribute charges to reach equilibrium.
- Since they are identical, charges will be shared equally between them.
- Final charge after contact = (2C + 4C) / 2 = 3C for both bodies.

4. **Charge Distribution:**
- Since the total charge before and after contact is the same (2C), the number of excess or deficient electrons in each body can be determined by comparing their charges before and after contact.
- Excess or deficient charge in body A = Final charge - Initial charge = 3C - (-2C) = 5C
- Excess or deficient charge in body B = Final charge - Initial charge = 3C - 4C = -1C

5. **Calculating the Number of Excess or Deficient Electrons:**
- The charge on an electron is -1.6 x 10^-19 C.
- Number of excess or deficient electrons in body A = (Excess or deficient charge in body A) / (Charge on an electron)
- Number of excess or deficient electrons in body A = 5C / (-1.6 x 10^-19 C)
- Number of excess or deficient electrons in body A = -3.125 x 10^19 electrons.
- Number of excess or deficient electrons in body B = (Excess or deficient charge in body B) / (Charge on an electron)
- Number of excess or deficient electrons in body B = -1C / (-1.6 x 10^-19 C)
- Number of excess or deficient electrons in body B = 6.25 x 10^18 electrons.

Therefore, the number of excess or deficient electrons in body A is 3.125 x 10^19 electrons (Option 1), and the number of excess or deficient electrons in body B is 6.25 x 10^18 electrons (Option 3).
Community Answer
Two identical spherical conducting bodies A and B carries charges 2C a...
6.25×10^18in deficient
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Two identical spherical conducting bodies A and B carries charges 2C and 8C respectively.Now a -4C charge is added to both of them and then they are made in contact for some time.The number of electrons present in excess/deficient in them are 1)2.5×10^16 in excess 2)2.5×10^16 in deficient 3)6.25×10^18 in deficient 4)3.375×10^18in excess?
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Two identical spherical conducting bodies A and B carries charges 2C and 8C respectively.Now a -4C charge is added to both of them and then they are made in contact for some time.The number of electrons present in excess/deficient in them are 1)2.5×10^16 in excess 2)2.5×10^16 in deficient 3)6.25×10^18 in deficient 4)3.375×10^18in excess? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two identical spherical conducting bodies A and B carries charges 2C and 8C respectively.Now a -4C charge is added to both of them and then they are made in contact for some time.The number of electrons present in excess/deficient in them are 1)2.5×10^16 in excess 2)2.5×10^16 in deficient 3)6.25×10^18 in deficient 4)3.375×10^18in excess? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical spherical conducting bodies A and B carries charges 2C and 8C respectively.Now a -4C charge is added to both of them and then they are made in contact for some time.The number of electrons present in excess/deficient in them are 1)2.5×10^16 in excess 2)2.5×10^16 in deficient 3)6.25×10^18 in deficient 4)3.375×10^18in excess?.
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