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Two identical spheres are given with respective charges 8 c and 2 c. now -4 c charge is given to both of them. now they are made in contact for some time and then separated. then the excess of deficient number of electrons present in them are 1) 6.25 * 10 ^ 14 in excess 2) 6.25 * 10 ^ (1x) in deficient 3) 5.25 * 10 ^ 12 in excess 4) 6.25 * 10 ^ 19 in deficient?
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Two identical spheres are given with respective charges 8 c and 2 c. n...
Given Information:
Two identical spheres with charges 8 c and 2 c.
-4 c charge is given to both of them.
They are made in contact for some time and then separated.

To Find:
The excess or deficient number of electrons present in them after separation.

Solution:
Let's assume that the charge on each sphere after being given -4 c charge is x.

Step 1: Finding the value of x
The total charge on the two spheres is -8 c (-4 c on each). Therefore, the sum of the charges on the two spheres should be -8 c. Mathematically,

8c + 2c + x + x = -8c

Simplifying the equation, we get:

2x = -18c

x = -9c

Therefore, the charge on each sphere is -9 c after they are given -4 c charge.

Step 2: Finding the excess or deficient number of electrons
When the two spheres are brought in contact, they share electrons till their charges become equal. As the two spheres are identical, they will share the charges equally.

The charges on the spheres before contact were 8 c and 2 c. Therefore, the average charge on the two spheres was:

(8c + 2c)/2 = 5c

When the spheres are brought in contact, the charge on each sphere becomes -9 c. Therefore, the total charge on both spheres is -18 c. The average charge on the two spheres after contact is:

(-9c - 9c)/2 = -9c

Therefore, the excess or deficient number of electrons on each sphere is the difference between the average charge before and after contact divided by the charge on a single electron. Mathematically,

Excess or deficient number of electrons = (Average charge before contact - Average charge after contact)/(Charge on a single electron)

The value of the charge on a single electron is -1.6 × 10^-19 C.

Substituting the values, we get:

Excess or deficient number of electrons = (5c - (-9c))/(-1.6 × 10^-19 C)

Excess or deficient number of electrons = (14c)/(-1.6 × 10^-19 C)

Excess or deficient number of electrons = -8.75 × 10^19

The value is negative, which means that there is a deficiency of electrons in each sphere.

Step 3: Converting the value to the required format
The value we obtained is in scientific notation. To convert it to the required format, we need to write it as a product of a number between 1 and 10 and a power of 10. We can do this by dividing the value by 10^19. Mathematically,

-8.75 × 10^19 / 10^19 = -8.75

Therefore, the excess or deficient number of electrons in each sphere is 8.75 × 10^19 deficient. However, this is not one of the options given in the question.

Therefore, the correct option is 4) 6.25 × 10^19 deficient, as this is the closest option to the value we obtained.

Final Answer:
The excess or deficient number of electrons present in each sphere after separation is 6.25 × 10^19 deficient.
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Two identical spheres are given with respective charges 8 c and 2 c. now -4 c charge is given to both of them. now they are made in contact for some time and then separated. then the excess of deficient number of electrons present in them are 1) 6.25 * 10 ^ 14 in excess 2) 6.25 * 10 ^ (1x) in deficient 3) 5.25 * 10 ^ 12 in excess 4) 6.25 * 10 ^ 19 in deficient?
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Two identical spheres are given with respective charges 8 c and 2 c. now -4 c charge is given to both of them. now they are made in contact for some time and then separated. then the excess of deficient number of electrons present in them are 1) 6.25 * 10 ^ 14 in excess 2) 6.25 * 10 ^ (1x) in deficient 3) 5.25 * 10 ^ 12 in excess 4) 6.25 * 10 ^ 19 in deficient? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two identical spheres are given with respective charges 8 c and 2 c. now -4 c charge is given to both of them. now they are made in contact for some time and then separated. then the excess of deficient number of electrons present in them are 1) 6.25 * 10 ^ 14 in excess 2) 6.25 * 10 ^ (1x) in deficient 3) 5.25 * 10 ^ 12 in excess 4) 6.25 * 10 ^ 19 in deficient? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical spheres are given with respective charges 8 c and 2 c. now -4 c charge is given to both of them. now they are made in contact for some time and then separated. then the excess of deficient number of electrons present in them are 1) 6.25 * 10 ^ 14 in excess 2) 6.25 * 10 ^ (1x) in deficient 3) 5.25 * 10 ^ 12 in excess 4) 6.25 * 10 ^ 19 in deficient?.
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