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the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes
Verified Answer
the constant force resisting the motion of car of mass 1500kg is equal...
V = 48km/hr
V = 40/3 = 13.33 m/s
v^2 - u^2 = 2as
0 - (40/3)^2 = 2*a*50
a = -16/9
|a| = 16/9 m/s^2
But a = 1/15(g) + additional acceleration
additional acceleration = 16/9 - 1/15(9.81)
additional acceleration = 1.12377
f = ma
additional force = m* additional acceleration
additional force = 1500*1.12377
= 1685.667 kg.m/s^2
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the constant force resisting the motion of car of mass 1500kg is equal...
The problem provides information about a car of mass 1500 kg, traveling at a speed of 48 km/h, being brought to rest in a distance of 50 m by applying brakes. We are asked to find the additional retarding force due to the brakes and the heat developed in the brakes.
Given data:
- Mass of the car (m) = 1500 kg
- Speed of the car (v) = 48 km/h = 13.33 m/s
- Distance traveled (d) = 50 m
To calculate the additional retarding force due to the brakes, we can use the equation:
Force (F) = mass (m) × acceleration (a)
The acceleration can be calculated using the kinematic equation:
v² = u² + 2as
Where:
- v is the final velocity (0 m/s since the car is brought to rest)
- u is the initial velocity (13.33 m/s)
- a is the acceleration
- s is the distance traveled (50 m)
Rearranging the equation, we get:
a = (v² - u²) / (2s)
Substituting the given values, we find:
a = (0² - 13.33²) / (2 × 50)
a = -133.28 / 100
a = -1.33 m/s²
The negative sign indicates that the acceleration is in the opposite direction of motion, which represents deceleration or retardation.
Now, we can calculate the additional retarding force:
Force (F) = mass (m) × acceleration (a)
F = 1500 kg × -1.33 m/s²
F = -1995 N
The negative sign indicates that the force is in the opposite direction of motion, opposing the car's movement.
To calculate the heat developed in the brakes, we can use the equation:
Heat (Q) = Force (F) × distance traveled (d)
Q = -1995 N × 50 m
Q = -99750 J
The negative sign indicates that heat is being dissipated from the brakes due to the work done against the retarding force.
In conclusion, the additional retarding force due to the brakes is -1995 N, and the heat developed in the brakes is -99750 J. The negative signs indicate the opposite direction of motion and the dissipation of heat from the brakes.
Given data:
- Mass of the car (m) = 1500 kg
- Speed of the car (v) = 48 km/h = 13.33 m/s
- Distance traveled (d) = 50 m
To calculate the additional retarding force due to the brakes, we can use the equation:
Force (F) = mass (m) × acceleration (a)
The acceleration can be calculated using the kinematic equation:
v² = u² + 2as
Where:
- v is the final velocity (0 m/s since the car is brought to rest)
- u is the initial velocity (13.33 m/s)
- a is the acceleration
- s is the distance traveled (50 m)
Rearranging the equation, we get:
a = (v² - u²) / (2s)
Substituting the given values, we find:
a = (0² - 13.33²) / (2 × 50)
a = -133.28 / 100
a = -1.33 m/s²
The negative sign indicates that the acceleration is in the opposite direction of motion, which represents deceleration or retardation.
Now, we can calculate the additional retarding force:
Force (F) = mass (m) × acceleration (a)
F = 1500 kg × -1.33 m/s²
F = -1995 N
The negative sign indicates that the force is in the opposite direction of motion, opposing the car's movement.
To calculate the heat developed in the brakes, we can use the equation:
Heat (Q) = Force (F) × distance traveled (d)
Q = -1995 N × 50 m
Q = -99750 J
The negative sign indicates that heat is being dissipated from the brakes due to the work done against the retarding force.
In conclusion, the additional retarding force due to the brakes is -1995 N, and the heat developed in the brakes is -99750 J. The negative signs indicate the opposite direction of motion and the dissipation of heat from the brakes.
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the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes
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the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes.
the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for the constant force resisting the motion of car of mass 1500kg is equal to one fifteen if it's weight if when traveling@48kmph car is bought to rest in a distance of 50m by applying brakes find additional retarding force due to brakes(assume constant) and heat developed in brakes.
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