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One mole of an ideal gas is compressed from 5 L to 2 L at constant temperature. The change in
entropy, in J K-1, of the gas is ____________. (R = 8.314 J K-1 mol-1)
entropy, in J K-1, of the gas is ____________. (R = 8.314 J K-1 mol-1)
Correct answer is between '-7.65,-7.48'. Can you explain this answer?
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One mole of an ideal gas is compressed from 5 L to 2 L at constant tem...
Solution:
Given,
Number of moles, n = 1 mol
Initial volume, Vi = 5 L
Final volume, Vf = 2 L
Gas constant, R = 8.314 J K-1 mol-1
Temperature, T = constant
The change in entropy of the gas can be calculated using the formula:
ΔS = nR ln(Vf/Vi)
Substituting the given values, we get
ΔS = (1 mol) (8.314 J K-1 mol-1) ln(2 L / 5 L)
ΔS = -7.57 J K-1 (approx)
Therefore, the change in entropy of the gas is between -7.65 and -7.48 J K-1.
Explanation:
The change in entropy of the gas is given by the formula ΔS = nR ln(Vf/Vi), where n is the number of moles of the gas, R is the gas constant, Vf is the final volume, and Vi is the initial volume.
In this case, the gas is compressed from 5 L to 2 L at constant temperature. As the temperature is constant, the gas is an ideal gas, and the compression is reversible.
Using the formula, we can calculate the change in entropy of the gas. The natural logarithm of the ratio of the final and initial volumes is negative, indicating a decrease in entropy.
Substituting the given values, we get the change in entropy of the gas as -7.57 J K-1.
Therefore, the correct answer is between -7.65 and -7.48 J K-1.
Given,
Number of moles, n = 1 mol
Initial volume, Vi = 5 L
Final volume, Vf = 2 L
Gas constant, R = 8.314 J K-1 mol-1
Temperature, T = constant
The change in entropy of the gas can be calculated using the formula:
ΔS = nR ln(Vf/Vi)
Substituting the given values, we get
ΔS = (1 mol) (8.314 J K-1 mol-1) ln(2 L / 5 L)
ΔS = -7.57 J K-1 (approx)
Therefore, the change in entropy of the gas is between -7.65 and -7.48 J K-1.
Explanation:
The change in entropy of the gas is given by the formula ΔS = nR ln(Vf/Vi), where n is the number of moles of the gas, R is the gas constant, Vf is the final volume, and Vi is the initial volume.
In this case, the gas is compressed from 5 L to 2 L at constant temperature. As the temperature is constant, the gas is an ideal gas, and the compression is reversible.
Using the formula, we can calculate the change in entropy of the gas. The natural logarithm of the ratio of the final and initial volumes is negative, indicating a decrease in entropy.
Substituting the given values, we get the change in entropy of the gas as -7.57 J K-1.
Therefore, the correct answer is between -7.65 and -7.48 J K-1.
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Community Answer
One mole of an ideal gas is compressed from 5 L to 2 L at constant tem...
S=R ln(V2/V1)
=8.314 ln(2/5)
=8.314 × (-0.916)
= -7.61
=8.314 ln(2/5)
=8.314 × (-0.916)
= -7.61
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One mole of an ideal gas is compressed from 5 L to 2 L at constant temperature. The change inentropy, in J K-1, of the gas is ____________. (R = 8.314 J K-1 mol-1)Correct answer is between '-7.65,-7.48'. Can you explain this answer?
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One mole of an ideal gas is compressed from 5 L to 2 L at constant temperature. The change inentropy, in J K-1, of the gas is ____________. (R = 8.314 J K-1 mol-1)Correct answer is between '-7.65,-7.48'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about One mole of an ideal gas is compressed from 5 L to 2 L at constant temperature. The change inentropy, in J K-1, of the gas is ____________. (R = 8.314 J K-1 mol-1)Correct answer is between '-7.65,-7.48'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One mole of an ideal gas is compressed from 5 L to 2 L at constant temperature. The change inentropy, in J K-1, of the gas is ____________. (R = 8.314 J K-1 mol-1)Correct answer is between '-7.65,-7.48'. Can you explain this answer?.
One mole of an ideal gas is compressed from 5 L to 2 L at constant temperature. The change inentropy, in J K-1, of the gas is ____________. (R = 8.314 J K-1 mol-1)Correct answer is between '-7.65,-7.48'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about One mole of an ideal gas is compressed from 5 L to 2 L at constant temperature. The change inentropy, in J K-1, of the gas is ____________. (R = 8.314 J K-1 mol-1)Correct answer is between '-7.65,-7.48'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One mole of an ideal gas is compressed from 5 L to 2 L at constant temperature. The change inentropy, in J K-1, of the gas is ____________. (R = 8.314 J K-1 mol-1)Correct answer is between '-7.65,-7.48'. Can you explain this answer?.
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