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A normal woman marries an albino man. They have both albino and normal children. The woman is :
- a)homozygous normal
- b)heterozygous normal
- c)homozygous recessive
- d)homozygous dominant
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A normal woman marries an albino man. They have both albino and normal...
Explanation:
Genetic makeup of parents:
- The woman is a normal (non-albino) woman, which means she has two copies of the dominant allele (A) for pigmentation.
- The man is an albino, which means he has two copies of the recessive allele (a) for pigmentation.
Possible genotypes of the parents:
- The woman can be either homozygous dominant (AA) or heterozygous (Aa) for pigmentation.
- The man is homozygous recessive (aa) for pigmentation.
Possible outcomes of their offspring:
- If the woman is homozygous dominant (AA), all of their offspring will be normal (Aa) because they will inherit one dominant allele (A) from the mother and one recessive allele (a) from the father.
- If the woman is heterozygous (Aa), their offspring will have a 50% chance of being normal (Aa) and a 50% chance of being albino (aa) because they can inherit either the dominant allele (A) or the recessive allele (a) from the mother, and they will always inherit the recessive allele (a) from the father.
Conclusion:
Since the couple has both albino and normal children, the woman must be heterozygous (Aa) for pigmentation.
Genetic makeup of parents:
- The woman is a normal (non-albino) woman, which means she has two copies of the dominant allele (A) for pigmentation.
- The man is an albino, which means he has two copies of the recessive allele (a) for pigmentation.
Possible genotypes of the parents:
- The woman can be either homozygous dominant (AA) or heterozygous (Aa) for pigmentation.
- The man is homozygous recessive (aa) for pigmentation.
Possible outcomes of their offspring:
- If the woman is homozygous dominant (AA), all of their offspring will be normal (Aa) because they will inherit one dominant allele (A) from the mother and one recessive allele (a) from the father.
- If the woman is heterozygous (Aa), their offspring will have a 50% chance of being normal (Aa) and a 50% chance of being albino (aa) because they can inherit either the dominant allele (A) or the recessive allele (a) from the mother, and they will always inherit the recessive allele (a) from the father.
Conclusion:
Since the couple has both albino and normal children, the woman must be heterozygous (Aa) for pigmentation.
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Community Answer
A normal woman marries an albino man. They have both albino and normal...
It because of Heterozygus individuals is a diploid organisms with two alleles, each of a different type. So that's why Heterozygus individuals have many many variations of a gene present in the population.
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A normal woman marries an albino man. They have both albino and normal children. The woman is :a) homozygous normal b) heterozygous normal c) homozygous recessive d) homozygous dominant Correct answer is option 'B'. Can you explain this answer?
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