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A normal woman marries an albino man. They have both albino and normal children. The woman is :
- a)homozygous normal
- b)heterozygous normal
- c)homozygous recessive
- d)homozygous dominant
Correct answer is option 'B'. Can you explain this answer?
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A normal woman marries an albino man. They have both albino and normal...
Albino is a sex linked ressisve inheritance character.if her childrens are albino (homozygous ressisve) and normal (homozygous or heterozygous ressisve) . therefore she should be a heterozygous ressisve but normal
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A normal woman marries an albino man. They have both albino and normal...
The Answer is Option 'B' - Heterozygous Normal
The answer to this question lies in understanding the principles of inheritance and the genetic makeup of the individuals involved. Let's break down the given information and analyze it step by step.
Understanding the Genetic Makeup
In humans, the gene responsible for albinism is recessive, meaning that a person needs to inherit two copies of the albino gene (one from each parent) to express the albino trait. The gene for normal pigmentation is dominant, meaning that if a person has at least one copy of the normal gene, they will express the normal phenotype.
Marriage between a Normal Woman and an Albino Man
When a normal woman (homozygous dominant) marries an albino man (homozygous recessive), their genetic makeup can be represented as follows:
- Normal woman: NN (where N represents the normal gene)
- Albino man: nn (where n represents the albino gene)
Inheritance of Genes to Children
The inheritance of genes from parents to children follows specific patterns. In this case, there are two possible scenarios for the couple's children:
1. If the woman is homozygous normal (NN) and the man is homozygous recessive (nn):
- All the children will be heterozygous for normal pigmentation (Nn). They will have one copy of the normal gene from the mother (N) and one copy of the albino gene from the father (n).
- Therefore, none of the children will express the albino phenotype, as the normal gene is dominant over the albino gene.
2. If the woman is heterozygous normal (Nn) and the man is homozygous recessive (nn):
- There is a 50% chance for each child to inherit the normal gene (N) from the mother and the albino gene (n) from the father, resulting in heterozygous normal children (Nn).
- There is also a 50% chance for each child to inherit the albino gene (n) from both parents, resulting in albino children (nn).
Conclusion
Since the couple has both albino and normal children, it can be concluded that the woman is heterozygous normal (Nn). She has one copy of the normal gene (N) and one copy of the albino gene (n). This genetic makeup allows for the inheritance of both normal and albino traits, resulting in a combination of phenotypes in their children.
The answer to this question lies in understanding the principles of inheritance and the genetic makeup of the individuals involved. Let's break down the given information and analyze it step by step.
Understanding the Genetic Makeup
In humans, the gene responsible for albinism is recessive, meaning that a person needs to inherit two copies of the albino gene (one from each parent) to express the albino trait. The gene for normal pigmentation is dominant, meaning that if a person has at least one copy of the normal gene, they will express the normal phenotype.
Marriage between a Normal Woman and an Albino Man
When a normal woman (homozygous dominant) marries an albino man (homozygous recessive), their genetic makeup can be represented as follows:
- Normal woman: NN (where N represents the normal gene)
- Albino man: nn (where n represents the albino gene)
Inheritance of Genes to Children
The inheritance of genes from parents to children follows specific patterns. In this case, there are two possible scenarios for the couple's children:
1. If the woman is homozygous normal (NN) and the man is homozygous recessive (nn):
- All the children will be heterozygous for normal pigmentation (Nn). They will have one copy of the normal gene from the mother (N) and one copy of the albino gene from the father (n).
- Therefore, none of the children will express the albino phenotype, as the normal gene is dominant over the albino gene.
2. If the woman is heterozygous normal (Nn) and the man is homozygous recessive (nn):
- There is a 50% chance for each child to inherit the normal gene (N) from the mother and the albino gene (n) from the father, resulting in heterozygous normal children (Nn).
- There is also a 50% chance for each child to inherit the albino gene (n) from both parents, resulting in albino children (nn).
Conclusion
Since the couple has both albino and normal children, it can be concluded that the woman is heterozygous normal (Nn). She has one copy of the normal gene (N) and one copy of the albino gene (n). This genetic makeup allows for the inheritance of both normal and albino traits, resulting in a combination of phenotypes in their children.
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A normal woman marries an albino man. They have both albino and normal children. The woman is :a) homozygous normal b) heterozygous normal c) homozygous recessive d) homozygous dominant Correct answer is option 'B'. Can you explain this answer?
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