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If a1 + a2 + a3 +.... + an = 3(2n+1 - 2), for every n ≥ 1, then a11 equals
Correct answer is '6144'. Can you explain this answer?
Most Upvoted Answer
If a1 + a2 + a3 +.... + an = 3(2n+1 - 2), for every n ≥ 1, then a11 e...
11th term of series = a11 = Sum of 11 terms - Sum of 10 terms = 3(211+1 - 2) - 3(210+1 - 2)
= 3(212 - 2 - 211 + 2) = 3(211)(2 - 1)= 3*211 = 6144
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If a1 + a2 + a3 +.... + an = 3(2n+1 - 2), for every n ≥ 1, then a11 e...
Solution:
Given, a1, a2, a3, .... an = 3(2n - 1), for every n ≥ 1
We need to find the value of a11.
Substituting the value of n = 11 in the given equation, we get
a11 = 3(2 × 11 - 1)
a11 = 3(22 - 1)
a11 = 3(21)
a11 = 63
Therefore, a11 = 63.
Explanation:
To solve the given problem, we need to substitute the value of n=11 in the given equation to find the value of a11. The given equation is a sequence of numbers where each term is obtained by substituting the value of n in the equation. We can find the value of any term in the sequence by substituting the value of n in the equation.
Steps:
1. Substitute n = 11 in the given equation.
2. Simplify the equation to get the value of a11.
3. The value of a11 is 63.
Hence, the correct answer is 63.
Given, a1, a2, a3, .... an = 3(2n - 1), for every n ≥ 1
We need to find the value of a11.
Substituting the value of n = 11 in the given equation, we get
a11 = 3(2 × 11 - 1)
a11 = 3(22 - 1)
a11 = 3(21)
a11 = 63
Therefore, a11 = 63.
Explanation:
To solve the given problem, we need to substitute the value of n=11 in the given equation to find the value of a11. The given equation is a sequence of numbers where each term is obtained by substituting the value of n in the equation. We can find the value of any term in the sequence by substituting the value of n in the equation.
Steps:
1. Substitute n = 11 in the given equation.
2. Simplify the equation to get the value of a11.
3. The value of a11 is 63.
Hence, the correct answer is 63.
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If a1 + a2 + a3 +.... + an = 3(2n+1 - 2), for every n ≥ 1, then a11 equalsCorrect answer is '6144'. Can you explain this answer?
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