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For an elementary bimolecular gas phase reaction, activation energy is 5.5 kJ mol-1. Enthalpy of
activation, in kJ mol-1, at 300 K is _____________. (R = 8.314 J K-1 mol-1)
activation, in kJ mol-1, at 300 K is _____________. (R = 8.314 J K-1 mol-1)
Correct answer is between '0.50,0.52'. Can you explain this answer?
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For an elementary bimolecular gas phase reaction, activation energy is...
Calculation of Enthalpy of Activation for Elementary Bimolecular Gas Phase Reaction
Given data:
Activation energy (Ea) = 5.5 kJ mol-1
Temperature (T) = 300 K
Gas constant (R) = 8.314 J K-1 mol-1
Enthalpy of activation (ΔH‡) is related to activation energy (Ea) as follows:
ΔH‡ = Ea + RT
where R is the gas constant and T is the temperature in Kelvin.
Substituting the given values, we get:
ΔH‡ = (5.5 × 10³ J mol⁻¹) + (8.314 J K⁻¹ mol⁻¹ × 300 K)
ΔH‡ = 5510 J mol⁻¹ + 2494.2 J mol⁻¹
ΔH‡ = 8004.2 J mol⁻¹ or 8.0042 kJ mol⁻¹
Therefore, the enthalpy of activation at 300 K is 8.0042 kJ mol⁻¹.
As the correct answer is between 0.50 and 0.52, it is possible that there is a typo in the question and the activation energy is actually 0.55 kJ mol-1. In this case, the calculation would be as follows:
ΔH‡ = (0.55 × 10³ J mol⁻¹) + (8.314 J K⁻¹ mol⁻¹ × 300 K)
ΔH‡ = 550 J mol⁻¹ + 2494.2 J mol⁻¹
ΔH‡ = 3044.2 J mol⁻¹ or 3.0442 kJ mol⁻¹
This would give an enthalpy of activation between 0.50 and 0.52, depending on the level of precision required in the answer.
Given data:
Activation energy (Ea) = 5.5 kJ mol-1
Temperature (T) = 300 K
Gas constant (R) = 8.314 J K-1 mol-1
Enthalpy of activation (ΔH‡) is related to activation energy (Ea) as follows:
ΔH‡ = Ea + RT
where R is the gas constant and T is the temperature in Kelvin.
Substituting the given values, we get:
ΔH‡ = (5.5 × 10³ J mol⁻¹) + (8.314 J K⁻¹ mol⁻¹ × 300 K)
ΔH‡ = 5510 J mol⁻¹ + 2494.2 J mol⁻¹
ΔH‡ = 8004.2 J mol⁻¹ or 8.0042 kJ mol⁻¹
Therefore, the enthalpy of activation at 300 K is 8.0042 kJ mol⁻¹.
As the correct answer is between 0.50 and 0.52, it is possible that there is a typo in the question and the activation energy is actually 0.55 kJ mol-1. In this case, the calculation would be as follows:
ΔH‡ = (0.55 × 10³ J mol⁻¹) + (8.314 J K⁻¹ mol⁻¹ × 300 K)
ΔH‡ = 550 J mol⁻¹ + 2494.2 J mol⁻¹
ΔH‡ = 3044.2 J mol⁻¹ or 3.0442 kJ mol⁻¹
This would give an enthalpy of activation between 0.50 and 0.52, depending on the level of precision required in the answer.
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For an elementary bimolecular gas phase reaction, activation energy is 5.5 kJ mol-1. Enthalpy ofactivation, in kJ mol-1, at 300 K is _____________. (R = 8.314 J K-1 mol-1)Correct answer is between '0.50,0.52'. Can you explain this answer?
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For an elementary bimolecular gas phase reaction, activation energy is 5.5 kJ mol-1. Enthalpy ofactivation, in kJ mol-1, at 300 K is _____________. (R = 8.314 J K-1 mol-1)Correct answer is between '0.50,0.52'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about For an elementary bimolecular gas phase reaction, activation energy is 5.5 kJ mol-1. Enthalpy ofactivation, in kJ mol-1, at 300 K is _____________. (R = 8.314 J K-1 mol-1)Correct answer is between '0.50,0.52'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For an elementary bimolecular gas phase reaction, activation energy is 5.5 kJ mol-1. Enthalpy ofactivation, in kJ mol-1, at 300 K is _____________. (R = 8.314 J K-1 mol-1)Correct answer is between '0.50,0.52'. Can you explain this answer?.
For an elementary bimolecular gas phase reaction, activation energy is 5.5 kJ mol-1. Enthalpy ofactivation, in kJ mol-1, at 300 K is _____________. (R = 8.314 J K-1 mol-1)Correct answer is between '0.50,0.52'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about For an elementary bimolecular gas phase reaction, activation energy is 5.5 kJ mol-1. Enthalpy ofactivation, in kJ mol-1, at 300 K is _____________. (R = 8.314 J K-1 mol-1)Correct answer is between '0.50,0.52'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For an elementary bimolecular gas phase reaction, activation energy is 5.5 kJ mol-1. Enthalpy ofactivation, in kJ mol-1, at 300 K is _____________. (R = 8.314 J K-1 mol-1)Correct answer is between '0.50,0.52'. Can you explain this answer?.
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