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For a gas phase unimolecular reaction at temperature 298 K, with a pre-exponential factor of 2.17 × 1013 s–1, the entropy of activation (J K–1 mol–1) is _______________
    Correct answer is between '10.2,10.6'. Can you explain this answer?
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    For a gas phase unimolecular reaction at temperature 298 K, with a pre...
    × 10^12 s^-1 and an activation energy of 150 kJ/mol, calculate the rate constant at 298 K.

    The rate constant (k) can be calculated using the Arrhenius equation:

    k = A e^(-Ea/RT)

    where A is the pre-exponential factor, Ea is the activation energy, R is the gas constant (8.314 J/mol*K), and T is the temperature in Kelvin.

    Plugging in the values given:

    A = 2.17 × 10^12 s^-1
    Ea = 150 kJ/mol = 150,000 J/mol
    R = 8.314 J/mol*K
    T = 298 K

    k = 2.17 × 10^12 s^-1 e^(-150,000 J/mol / (8.314 J/mol*K * 298 K))

    Simplifying:

    k = 2.17 × 10^12 s^-1 e^(-50.59)

    k = 2.17 × 10^12 s^-1 * 1.81 × 10^-23

    k = 3.93 × 10^-11 s^-1

    Therefore, the rate constant for the gas phase unimolecular reaction at 298 K is 3.93 × 10^-11 s^-1.
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