A male human is heterozygous for autosomal genes A and B. He is also h...
Heterozygous for A and B ;Hemizygous for h.
Therefore the genotype would be:
AaBbXh Y
(hemizygous for h as in for human males can only fall on X)
(hemizygous for female would be Xh X)
All the kinds of gametes you can get with this,,,
abXh
ABXh
abY
AbY
aBX
aBY
ABY
AbXh
but they are asking for portion of abXh..
Therefore its 1 / 8
So, the correct answer is '1 / 8'.
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A male human is heterozygous for autosomal genes A and B. He is also h...
A male human is heterozygous for autosomal genes A and B. He is also h...
Given:
- Male human is heterozygous for autosomal genes A and B.
- He is also hemizygous for hemophilic gene h.
To find: Proportion of sperms that will carry abh.
Solution:
The male human has the following genotype:
- AaBb (heterozygous for autosomal genes A and B)
- XhY (hemizygous for hemophilic gene h)
The possible gametes he can produce are:
- ABXh (contains A, B, and h)
- AbXh (contains A, b, and h)
- aBXh (contains a, B, and h)
- abXh (contains a, b, and h)
Out of these four gametes, only one contains all three alleles (A, B, and h), which is ABXh.
Therefore, the proportion of sperms that will carry abh is 1 out of 8 (since there are 8 possible combinations of X and Y chromosomes in the male gametes).
Hence, the correct option is (a) 1 / 8.
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