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A double pipe counter flow heat exchanger is to be designed to cool 12000 kg/hr of an oil of specific heat 1.95 Kj/Kg-K . from 85oC to 55oC by water entering the heat exchanger at 30oC and leaving at 45oC . If the overall heat transfer coefficient of heat exchanger is 400 W/m2-. K Calculate the surface area of the heat exchanger.
(B) 15.5
Correct answer is between ','. Can you explain this answer?
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A double pipe counter flow heat exchanger is to be designed to cool 1...
For the counter flow heat exchanger
Mh = 12000/3600 = 3.33 kh/s
Cph = 1.95 kj/kh -K
Thi - 85oC; The = 55oC
Tci = 30oC; Tce = 45oC
∴ θ0 = 40oC; θ1 = 45oC
⇒ ፀm = 31.9oC
Q = mhcph(Thi - The) = 3.33 x 1.95(85-55)
⇒ Q = 194.805 kW
Again Q = UA(θm)
⇒ A = Q/u((θm)= 194.805/0.4 x 31.9
⇒ A = 15.27m2
Most Upvoted Answer
A double pipe counter flow heat exchanger is to be designed to cool 1...
Given data:
- Oil flow rate (m_dot_oil) = 12000 kg/hr = 3.33 kg/s
- Specific heat of oil (Cp_oil) = 1.95 kJ/kg-K
- Inlet temperature of oil (T_oil_in) = 85°C
- Outlet temperature of oil (T_oil_out) = 55°C
- Water inlet temperature (T_water_in) = 30°C
- Water outlet temperature (T_water_out) = 45°C
- Overall heat transfer coefficient (U) = 400 W/m2-K
Calculation of heat transfer:
The heat transfer rate (Q) can be calculated using the formula:
Q = m_dot_oil * Cp_oil * (T_oil_in - T_oil_out)
Substituting the given values:
Q = 3.33 kg/s * 1.95 kJ/kg-K * (85°C - 55°C)
Q = 3.33 * 1.95 * 30 kJ/s = 193.95 kW
Calculation of log mean temperature difference (LMTD):
The log mean temperature difference (LMTD) can be calculated using the formula:
LMTD = (ΔT1 - ΔT2) / ln(ΔT1 / ΔT2)
Where:
ΔT1 = T_oil_in - T_water_out
ΔT2 = T_oil_out - T_water_in
Substituting the given values:
ΔT1 = 85°C - 45°C = 40°C
ΔT2 = 55°C - 30°C = 25°C
LMTD = (40°C - 25°C) / ln(40°C / 25°C)
LMTD = 15°C / ln(1.6)
Using logarithmic tables or calculator, the natural logarithm of 1.6 is approximately 0.47.
LMTD = 15°C / 0.47
LMTD = 31.91°C
Calculation of surface area:
The heat transfer area (A) can be calculated using the formula:
Q = U * A * LMTD
Rearranging the formula:
A = Q / (U * LMTD)
Substituting the given values:
A = 193.95 kW / (400 W/m2-K * 31.91°C)
A = 484.875 m2
Conclusion:
The surface area of the double pipe counter flow heat exchanger required to cool 12000 kg/hr of oil from 85°C to 55°C using water entering at 30°C and leaving at 45°C, with an overall heat transfer coefficient of 400 W/m2-K, is approximately 484.875 m2.
- Oil flow rate (m_dot_oil) = 12000 kg/hr = 3.33 kg/s
- Specific heat of oil (Cp_oil) = 1.95 kJ/kg-K
- Inlet temperature of oil (T_oil_in) = 85°C
- Outlet temperature of oil (T_oil_out) = 55°C
- Water inlet temperature (T_water_in) = 30°C
- Water outlet temperature (T_water_out) = 45°C
- Overall heat transfer coefficient (U) = 400 W/m2-K
Calculation of heat transfer:
The heat transfer rate (Q) can be calculated using the formula:
Q = m_dot_oil * Cp_oil * (T_oil_in - T_oil_out)
Substituting the given values:
Q = 3.33 kg/s * 1.95 kJ/kg-K * (85°C - 55°C)
Q = 3.33 * 1.95 * 30 kJ/s = 193.95 kW
Calculation of log mean temperature difference (LMTD):
The log mean temperature difference (LMTD) can be calculated using the formula:
LMTD = (ΔT1 - ΔT2) / ln(ΔT1 / ΔT2)
Where:
ΔT1 = T_oil_in - T_water_out
ΔT2 = T_oil_out - T_water_in
Substituting the given values:
ΔT1 = 85°C - 45°C = 40°C
ΔT2 = 55°C - 30°C = 25°C
LMTD = (40°C - 25°C) / ln(40°C / 25°C)
LMTD = 15°C / ln(1.6)
Using logarithmic tables or calculator, the natural logarithm of 1.6 is approximately 0.47.
LMTD = 15°C / 0.47
LMTD = 31.91°C
Calculation of surface area:
The heat transfer area (A) can be calculated using the formula:
Q = U * A * LMTD
Rearranging the formula:
A = Q / (U * LMTD)
Substituting the given values:
A = 193.95 kW / (400 W/m2-K * 31.91°C)
A = 484.875 m2
Conclusion:
The surface area of the double pipe counter flow heat exchanger required to cool 12000 kg/hr of oil from 85°C to 55°C using water entering at 30°C and leaving at 45°C, with an overall heat transfer coefficient of 400 W/m2-K, is approximately 484.875 m2.
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A double pipe counter flow heat exchanger is to be designed to cool 12000 kg/hr of an oil of specific heat 1.95 Kj/Kg-K . from 85oC to 55oC by water entering the heat exchanger at 30oC and leaving at 45oC . If the overall heat transfer coefficient of heat exchanger is 400 W/m2-. K Calculate the surface area of the heat exchanger.(B) 15.5Correct answer is between ','. Can you explain this answer?
Question Description
A double pipe counter flow heat exchanger is to be designed to cool 12000 kg/hr of an oil of specific heat 1.95 Kj/Kg-K . from 85oC to 55oC by water entering the heat exchanger at 30oC and leaving at 45oC . If the overall heat transfer coefficient of heat exchanger is 400 W/m2-. K Calculate the surface area of the heat exchanger.(B) 15.5Correct answer is between ','. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A double pipe counter flow heat exchanger is to be designed to cool 12000 kg/hr of an oil of specific heat 1.95 Kj/Kg-K . from 85oC to 55oC by water entering the heat exchanger at 30oC and leaving at 45oC . If the overall heat transfer coefficient of heat exchanger is 400 W/m2-. K Calculate the surface area of the heat exchanger.(B) 15.5Correct answer is between ','. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A double pipe counter flow heat exchanger is to be designed to cool 12000 kg/hr of an oil of specific heat 1.95 Kj/Kg-K . from 85oC to 55oC by water entering the heat exchanger at 30oC and leaving at 45oC . If the overall heat transfer coefficient of heat exchanger is 400 W/m2-. K Calculate the surface area of the heat exchanger.(B) 15.5Correct answer is between ','. Can you explain this answer?.
A double pipe counter flow heat exchanger is to be designed to cool 12000 kg/hr of an oil of specific heat 1.95 Kj/Kg-K . from 85oC to 55oC by water entering the heat exchanger at 30oC and leaving at 45oC . If the overall heat transfer coefficient of heat exchanger is 400 W/m2-. K Calculate the surface area of the heat exchanger.(B) 15.5Correct answer is between ','. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A double pipe counter flow heat exchanger is to be designed to cool 12000 kg/hr of an oil of specific heat 1.95 Kj/Kg-K . from 85oC to 55oC by water entering the heat exchanger at 30oC and leaving at 45oC . If the overall heat transfer coefficient of heat exchanger is 400 W/m2-. K Calculate the surface area of the heat exchanger.(B) 15.5Correct answer is between ','. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A double pipe counter flow heat exchanger is to be designed to cool 12000 kg/hr of an oil of specific heat 1.95 Kj/Kg-K . from 85oC to 55oC by water entering the heat exchanger at 30oC and leaving at 45oC . If the overall heat transfer coefficient of heat exchanger is 400 W/m2-. K Calculate the surface area of the heat exchanger.(B) 15.5Correct answer is between ','. Can you explain this answer?.
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