In two containers A and B milk and water are in ratio 7:6 and 3:7 resp...
Given:
Ratio of milk and water in container A = 7:6
Ratio of milk and water in container B = 3:7
Ratio in which both the mixture are mixed = 4:3
To find:
Ratio of milk and water in the new mixture
Solution:
Let the quantity of mixture from container A be 7x and 6x, and from container B be 3y and 7y, respectively.
Then, the ratio in which the mixtures are mixed = 4:3, which means that the total quantity of the mixture is 4x+3y.
Now, we can find the quantity of milk and water in each container separately as follows:
Quantity of milk in container A = 7x/(7+6) = 7x/13
Quantity of water in container A = 6x/(7+6) = 6x/13
Quantity of milk in container B = 3y/(3+7) = 3y/10
Quantity of water in container B = 7y/(3+7) = 7y/10
Total quantity of milk in the mixture = (7x/13) * (4/7) + (3y/10) * (3/7) = (28x+9y)/91
Total quantity of water in the mixture = (6x/13) * (4/7) + (7y/10) * (3/7) = (24x+21y)/91
Therefore, the ratio of milk and water in the new mixture is:
(28x+9y)/(24x+21y)
We know that the total quantity of the mixture is 4x+3y, so we can write:
(28x+9y)/(24x+21y) = (7/13) * (4x+3y)/(3/10) * (4x+3y)
Simplifying this expression, we get:
(28x+9y)/(24x+21y) = 28/39
Therefore, the ratio of milk and water in the new mixture is:
28:39 = 397:513
Hence, the correct answer is option (c) 397:513.
In two containers A and B milk and water are in ratio 7:6 and 3:7 resp...