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A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.
The angle of inclination of the tube with the horizontal is:
  • a)
    sin -1 [ l/hd - aw/at ]
  • b)
    sin -1 [ hd/l + at/aw]
  • c)
    sin -1 [ hd/l - at/aw]
  • d)
    sin -1 [ hd/l + aw/at]
Correct answer is option 'C'. Can you explain this answer?
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A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? for GATE 2025 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer?.
Solutions for A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE. Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.
Here you can find the meaning of A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice GATE tests.
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