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A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? for GATE 2025 is part of GATE preparation. The Question and answers have been prepared
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the GATE exam syllabus. Information about A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2025 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer?.
Solutions for A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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Here you can find the meaning of A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A well of cross-sectional area aw is connected to an inclined tube of cross-sectional area at to form a differential pressure gauge as shown in the figure below. When p1 = p2 the common liquid level is denoted by A. When p1 > p2, the liquid level in the well is depressed to B, and the level in the tube rises by l along its length such that the difference in the tube and well levels is hd.The angle of inclination of the tube with the horizontal is:a)sin -1 [ l/hd - aw/at ]b)sin -1 [ hd/l + at/aw]c)sin -1 [ hd/l - at/aw]d)sin -1 [ hd/l + aw/at]Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice GATE tests.