An industrial consumer has a daily load patt...
An industrial consumer has a daily load pattern of 2000 kW, 0.8 lag for 12 hours and 1000 kW UPF for 12 hours. The load factor is-
• a)
0.5
• b)
0.75
• c)
0.6
• d)
2.0
Correct answer is option 'C'. Can you explain this answer?
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The load factor is a measure of how efficiently a consumer uses electricity. It is calculated as the ratio of the average load to the maximum demand during a given period of time. In this case, we need to calculate the load factor for an industrial consumer with a daily load pattern of 2000 kW, 0.8 lag for 12 hours, and 1000 kW UPF for 12 hours.

1. Calculate the average load:
To calculate the average load, we need to find the total energy consumed during the given period and divide it by the total time.

Average Load = (Energy consumed during 0.8 lag period + Energy consumed during UPF period) / Total time

Energy consumed during 0.8 lag period = 0.8 lag load * time
Energy consumed during UPF period = UPF load * time

Energy consumed during 0.8 lag period = 2000 kW * 0.8 lag * 12 hours
Energy consumed during UPF period = 1000 kW * 12 hours

Total energy consumed = Energy consumed during 0.8 lag period + Energy consumed during UPF period

Average Load = Total energy consumed / Total time

2. Calculate the maximum demand:
The maximum demand is the highest load recorded during the given period. In this case, the maximum demand is 2000 kW.

3. Calculate the load factor:
The load factor is the ratio of the average load to the maximum demand.

Load Factor = Average Load / Maximum Demand

Load Factor = (Total energy consumed / Total time) / Maximum Demand

Load Factor = (Energy consumed during 0.8 lag period + Energy consumed during UPF period) / (Total time * Maximum Demand)

Load Factor = [(2000 kW * 0.8 lag * 12 hours) + (1000 kW * 12 hours)] / (24 hours * 2000 kW)

Load Factor = (19200 kWh + 12000 kWh) / (48000 kWh)

Load Factor = 31200 kWh / 48000 kWh

Load Factor = 0.65

The correct answer is option 'C' (0.6).

Explanation:

The load factor is a measure of how efficiently a consumer uses electricity. In this case, the industrial consumer has a daily load pattern of 2000 kW, 0.8 lag for 12 hours, and 1000 kW UPF for 12 hours.

To calculate the load factor, we first need to calculate the average load and the maximum demand. The average load is calculated by finding the total energy consumed during the given period and dividing it by the total time.

The maximum demand is the highest load recorded during the given period, which in this case is 2000 kW.

By dividing the average load by the maximum demand, we can calculate the load factor. In this case, the load factor is calculated to be 0.65.

However, the correct answer given is option 'C' (0.6). It seems there might be an error in the answer provided. The load factor should be 0.65, not 0.6.
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An industrial consumer has a daily load pattern of 2000 kW, 0.8 lag for 12 hours and 1000 kW UPF for 12 hours. The load factor is-a)0.5b)0.75c)0.6d)2.0Correct answer is option 'C'. Can you explain this answer?
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