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For laminar flow in a pipe, average velocity is equal to:
  • a)
    2 Umax
  • b)
    Umax
  • c)
    0.5 Umax
  • d)
    0.25 Umax
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
For laminar flow in a pipe, average velocity is equal to:a)2 Umaxb)Um...
For a fully developed laminar viscous flow through a circular pipe, the maximum velocity is equal to twice the average velocity.
i.e. Vmax=2×Vavg
Vavg=0.5×Vmax
Point to be remembered:
For the fully developed laminar flow through the parallel plates, the maximum velocity is equal to the (3/2) times of the average velocity.
i.e.
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Most Upvoted Answer
For laminar flow in a pipe, average velocity is equal to:a)2 Umaxb)Um...
Laminar Flow in a Pipe and Average Velocity

Laminar flow is a type of flow in which the fluid moves in smooth layers or streams. It is characterized by low Reynolds numbers and is commonly observed in small diameter pipes. In laminar flow, the velocity of the fluid at any point is constant and does not change with time.

Average Velocity in Laminar Flow

The average velocity in laminar flow is the mean velocity of the fluid over the cross-sectional area of the pipe. It is a measure of the overall flow rate of the fluid and is given by the formula:

Vavg = (1/A) ∫v dA

where Vavg is the average velocity, A is the cross-sectional area of the pipe, v is the velocity of the fluid at a particular point, and ∫dA is the integration over the cross-sectional area of the pipe.

Calculation of Average Velocity

For laminar flow in a pipe, the velocity profile is parabolic in shape, with the maximum velocity occurring at the center of the pipe. The velocity at any point in the pipe can be expressed as:

v(r) = (4vmax/π) * (r/R)^2

where vmax is the maximum velocity at the center of the pipe, r is the radial distance from the center of the pipe, and R is the radius of the pipe.

Using this velocity profile, the average velocity can be calculated as:

Vavg = (2/3) vmax

Therefore, the correct answer is option C, which is 0.5 Umax.
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Community Answer
For laminar flow in a pipe, average velocity is equal to:a)2 Umaxb)Um...
For a fully developed laminar viscous flow through a circular pipe, the maximum velocity is equal to twice the average velocity.
i.e. Vmax=2×Vavg
Vavg=0.5×Vmax
Point to be remembered:
For the fully developed laminar flow through the parallel plates, the maximum velocity is equal to the (3/2) times of the average velocity.
i.e.
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For laminar flow in a pipe, average velocity is equal to:a)2 Umaxb)Umaxc)0.5 Umaxd)0.25 UmaxCorrect answer is option 'C'. Can you explain this answer?
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