Pinky walks a distance of 600 mtr. towards East, turns left, and moves 500 mtr. Then turns left and walks 600 mtr and then turns left again and moves 500 mtr and halts. At what distance in meters is she from the starting point?a)500b)600c)0d)2200Correct answer is option 'C'. Can you explain this answer?

Question

Answer

Therefore, since starting point is also the end point; Pinky

is 0 Km distance from the starting point.

Answer

Therefore, since starting point is also the end point; Pinky

is 0 Km distance from the starting point.

Answer

Solution:

Given:
Pinky walks a distance of 600 m towards East, turns left and moves 500 m.
Then turns left again and walks 600 m and turns left again and moves 500 m.

To find:
The distance of Pinky from the starting point.

Analysis:
Let's analyze Pinky's movements step by step:

1. Pinky walks 600 m towards East.
2. Then Pinky turns left and moves 500 m.
3. Again, Pinky turns left and walks 600 m.
4. Finally, Pinky turns left again and moves 500 m.

Finding the direction:
- Pinky initially walks towards East, then turns left three times.
- Turning left three times is equivalent to making a 270-degree clockwise rotation.
- Hence, Pinky is facing South at the end.

Finding the distance:
- Pinky moves 500 m and 500 m in two different instances, forming a rectangle.
- The sides of the rectangle are 600 m and 500 m.
- The distance between the starting point and the ending point will be the length of the diagonal of this rectangle.

Using the Pythagorean theorem, we can find the length of the diagonal (d):

d^2 = 600^2 + 500^2
d^2 = 360000 + 250000
d^2 = 610000
d = √610000
d ≈ 781.02 m

Therefore, Pinky is approximately 781.02 meters away from the starting point.

Conclusion:
The correct answer is option 'C' - 0 (zero).

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