SSC Exam  >  SSC Questions  >   An electric load consumed 17.32 kW at a powe... Start Learning for Free
An electric load consumed 17.32 kW at a power factor of 0.707 (lagging). For changing the load power factor to 0.866 (lagging), the capacitor that is to be connected in parallel with the load should draw-
  • a)
    7.32 kVAR
  • b)
    10 kVAR
  • c)
    27.32 kVAR
  • d)
    10.32 kVAR
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
An electric load consumed 17.32 kW at a power factor of 0.707 (laggin...
View all questions of this test
Most Upvoted Answer
An electric load consumed 17.32 kW at a power factor of 0.707 (laggin...
Calculation of Reactive Power Required

Given data:
Load power = 17.32 kW
Initial power factor (PF1) = 0.707 lagging
Final power factor (PF2) = 0.866 lagging

To calculate the reactive power required to improve the power factor, we can use the following formula:

Q = P x (tanθ1 – tanθ2)

Where Q is the reactive power required, P is the load power, θ1 is the initial phase angle, and θ2 is the final phase angle.

First, we need to calculate the initial and final phase angles using the power factors:

θ1 = cos⁻¹(PF1)
θ2 = cos⁻¹(PF2)

Substituting the given values:

θ1 = cos⁻¹(0.707) = 45.00°
θ2 = cos⁻¹(0.866) = 30.96°

Now, we can calculate the reactive power required:

Q = 17.32 x (tan45.00 – tan30.96) = 7.32 kVAR

Therefore, the capacitor required to improve the power factor should draw 7.32 kVAR of reactive power. Answer (a) is correct.
Explore Courses for SSC exam
An electric load consumed 17.32 kW at a power factor of 0.707 (lagging). For changing the load power factor to 0.866 (lagging), the capacitor that is to be connected in parallel with the load should draw-a)7.32 kVARb)10 kVARc)27.32 kVARd)10.32 kVARCorrect answer is option 'A'. Can you explain this answer?
Question Description
An electric load consumed 17.32 kW at a power factor of 0.707 (lagging). For changing the load power factor to 0.866 (lagging), the capacitor that is to be connected in parallel with the load should draw-a)7.32 kVARb)10 kVARc)27.32 kVARd)10.32 kVARCorrect answer is option 'A'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about An electric load consumed 17.32 kW at a power factor of 0.707 (lagging). For changing the load power factor to 0.866 (lagging), the capacitor that is to be connected in parallel with the load should draw-a)7.32 kVARb)10 kVARc)27.32 kVARd)10.32 kVARCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electric load consumed 17.32 kW at a power factor of 0.707 (lagging). For changing the load power factor to 0.866 (lagging), the capacitor that is to be connected in parallel with the load should draw-a)7.32 kVARb)10 kVARc)27.32 kVARd)10.32 kVARCorrect answer is option 'A'. Can you explain this answer?.
Solutions for An electric load consumed 17.32 kW at a power factor of 0.707 (lagging). For changing the load power factor to 0.866 (lagging), the capacitor that is to be connected in parallel with the load should draw-a)7.32 kVARb)10 kVARc)27.32 kVARd)10.32 kVARCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for SSC. Download more important topics, notes, lectures and mock test series for SSC Exam by signing up for free.
Here you can find the meaning of An electric load consumed 17.32 kW at a power factor of 0.707 (lagging). For changing the load power factor to 0.866 (lagging), the capacitor that is to be connected in parallel with the load should draw-a)7.32 kVARb)10 kVARc)27.32 kVARd)10.32 kVARCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of An electric load consumed 17.32 kW at a power factor of 0.707 (lagging). For changing the load power factor to 0.866 (lagging), the capacitor that is to be connected in parallel with the load should draw-a)7.32 kVARb)10 kVARc)27.32 kVARd)10.32 kVARCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for An electric load consumed 17.32 kW at a power factor of 0.707 (lagging). For changing the load power factor to 0.866 (lagging), the capacitor that is to be connected in parallel with the load should draw-a)7.32 kVARb)10 kVARc)27.32 kVARd)10.32 kVARCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of An electric load consumed 17.32 kW at a power factor of 0.707 (lagging). For changing the load power factor to 0.866 (lagging), the capacitor that is to be connected in parallel with the load should draw-a)7.32 kVARb)10 kVARc)27.32 kVARd)10.32 kVARCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice An electric load consumed 17.32 kW at a power factor of 0.707 (lagging). For changing the load power factor to 0.866 (lagging), the capacitor that is to be connected in parallel with the load should draw-a)7.32 kVARb)10 kVARc)27.32 kVARd)10.32 kVARCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice SSC tests.
Explore Courses for SSC exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev