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A transistor is operating in common emitter mode, as shown in the figure given below. The voltage (VCE) is-
  • a)
    10.05 V
  • b)
    1.5 V
  • c)
    1.05 V
  • d)
    0.5 V
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A transistor is operating in common emitter mode, as shown in the fig...
Let the transistor be in the active region then by applying Kirchoff's law to the base-emitter loop,
The transistor is operating in the active region. The initial assumption is valid.
Now, from collector to emitter loop,
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A transistor is operating in common emitter mode, as shown in the figure given below. The voltage (VCE) is-a)10.05 Vb)1.5 Vc)1.05 Vd)0.5 VCorrect answer is option 'C'. Can you explain this answer?
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