A 4-pole, 1200 rpm DC lap wound generator has 1520 conductors. If the flux per pole is 0.01 weber, the emf of the generator is -a)608 voltsb)304 voltsc)152 voltsd)76 voltsCorrect answer is option 'B'. Can you explain this answer?

Question

Answer

Solution:

Given,
P = 4 poles
N = 1200 rpm
Z = 1520 conductors
Φ = 0.01 weber

We know that the emf generated in a DC generator is given by the formula,

E = ΦNZ/60A

where A is the number of parallel paths in the armature winding.

For a lap winding, A = P.

Substituting the given values, we get

E = 0.01 x 4 x 1520 x 1200 / 60 x 4

E = 304 V

Therefore, the emf of the generator is 304 volts.

Hence, the correct option is (b) 304 volts.

Answer

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