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If the inductance and capacitance of a power system are respectively 1H and the instantaneous value of interrupted current is 10A, then the voltage across the breaker contacts will be -
  • a)
    50 kV
  • b)
    57 kV
  • c)
    60 kV
  • d)
    100 kV
Correct answer is option 'D'. Can you explain this answer?
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The voltage across the breaker contacts can be determined using the formula:

V = L * di/dt

1. Given values:
Inductance (L) = 1 H
Instantaneous current (di/dt) = 10 A

2. Substituting the values in the formula:
V = 1 * 10

3. Calculating the voltage:
V = 10 V

Therefore, the voltage across the breaker contacts is 10 V.

However, the given answer options are in kilovolts (kV), so we need to convert the voltage from volts to kilovolts.

1 kV = 1000 V

4. Converting voltage to kilovolts:
V = 10 V / 1000
V = 0.01 kV

Hence, the voltage across the breaker contacts is 0.01 kV, which does not match any of the given answer options.

Therefore, the given correct answer option is incorrect.

The correct answer cannot be determined with the given information.
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If the inductance and capacitance of a power system are respectively 1H and the instantaneous value of interrupted current is 10A, then the voltage across the breaker contacts will be -a)50 kVb)57 kVc)60 kVd)100 kVCorrect answer is option 'D'. Can you explain this answer?
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