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An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately-
- a)31Ω
- b)3.1Ω
- c)385Ω
- d)38.5Ω
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
An electric heater draws 3.5 A from a 110 V source. The resistance of ...
Calculating the resistance of the heating element:
- We know that Ohm's Law states V=IR, where V is the voltage, I is the current, and R is the resistance.
- Given that the electric heater draws 3.5 A from a 110 V source, we can use Ohm's Law to calculate the resistance.
- Plugging in the values, we get 110 V = 3.5 A * R. Solving for R gives us R = 110 V / 3.5 A = 31 Ω.
Therefore, the resistance of the heating element is approximately 31 Ω, which corresponds to option 'A'.
- We know that Ohm's Law states V=IR, where V is the voltage, I is the current, and R is the resistance.
- Given that the electric heater draws 3.5 A from a 110 V source, we can use Ohm's Law to calculate the resistance.
- Plugging in the values, we get 110 V = 3.5 A * R. Solving for R gives us R = 110 V / 3.5 A = 31 Ω.
Therefore, the resistance of the heating element is approximately 31 Ω, which corresponds to option 'A'.
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Community Answer
An electric heater draws 3.5 A from a 110 V source. The resistance of ...
R = 110/3.5 = 3.1Ω
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An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately-a)31Ωb)3.1Ωc)385Ωd)38.5ΩCorrect answer is option 'A'. Can you explain this answer?
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