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We have three resistance each of value 1 Ω, 2 Ω and 3 Ω. If all the three resistances are to be connected in a circuit, how many different values of equivalent resistance are possible?
- a)Five
- b)Six
- c)Seven
- d)Eight
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
We have three resistance each of value 1 Ω, 2 Ω and 3 &Ome...
Eight different values can be obtained if they are connected in different ways.
All three in series (1 combination)
All three in parallel (1 combination)
One in series two in parallel (3 combination)
Two in series one in parallel ( 3 combination)
Total Eight different values can be obtained if they are connected in different ways.
All three in series (1 combination)
All three in parallel (1 combination)
One in series two in parallel (3 combination)
Two in series one in parallel ( 3 combination)
Total = 1 + 1 + 3 + 3 = 8
All three in series (1 combination)
All three in parallel (1 combination)
One in series two in parallel (3 combination)
Two in series one in parallel ( 3 combination)
Total Eight different values can be obtained if they are connected in different ways.
All three in series (1 combination)
All three in parallel (1 combination)
One in series two in parallel (3 combination)
Two in series one in parallel ( 3 combination)
Total = 1 + 1 + 3 + 3 = 8
Most Upvoted Answer
We have three resistance each of value 1 Ω, 2 Ω and 3 &Ome...
If we have three resistors, each with a resistance value of 1, we can calculate the total resistance when they are connected in different ways.
1. Series connection: When resistors are connected in series, the total resistance is the sum of individual resistances. So, in this case, the total resistance would be 1 + 1 + 1 = 3.
2. Parallel connection: When resistors are connected in parallel, the total resistance is given by the reciprocal of the sum of the reciprocals of individual resistances. So, in this case, the total resistance would be 1/(1/1 + 1/1 + 1/1) = 1/(1 + 1 + 1) = 1/3.
Therefore, the total resistance in a series connection is 3 and in a parallel connection is 1/3 when three resistors of value 1 are used.
1. Series connection: When resistors are connected in series, the total resistance is the sum of individual resistances. So, in this case, the total resistance would be 1 + 1 + 1 = 3.
2. Parallel connection: When resistors are connected in parallel, the total resistance is given by the reciprocal of the sum of the reciprocals of individual resistances. So, in this case, the total resistance would be 1/(1/1 + 1/1 + 1/1) = 1/(1 + 1 + 1) = 1/3.
Therefore, the total resistance in a series connection is 3 and in a parallel connection is 1/3 when three resistors of value 1 are used.
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We have three resistance each of value 1 Ω, 2 Ω and 3 Ω. If all the three resistances are to be connected in a circuit, how many different values of equivalent resistance are possible?a)Fiveb)Sixc)Sevend)EightCorrect answer is option 'D'. Can you explain this answer?
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