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Three inductors each of 60 mH are connected in delta. The value of inductance of each arm of the equivalent star connection is-
- a)10 mH
- b)15 mH
- c)20 mH
- d)30 mH
Correct answer is option 'C'. Can you explain this answer?
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Three inductors each of 60 mH are connected in delta. The value of in...
Lab = L/3 = 60/3 x 10-3 = 20mH
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Three inductors each of 60 mH are connected in delta. The value of in...
To find the value of inductance of each arm in the equivalent star connection, we can use the following formula:
Ls = (L1 * L2 + L2 * L3 + L3 * L1) / (L1 + L2 + L3)
Given that each inductor has a value of 60 mH, we can substitute this value into the formula to find the equivalent star connection inductance.
Let's calculate step by step:
1. Substitute the given values into the formula:
Ls = (60 * 60 + 60 * 60 + 60 * 60) / (60 + 60 + 60)
2. Simplify the equation:
Ls = (3600 + 3600 + 3600) / 180
3. Add the values in the numerator:
Ls = 10800 / 180
4. Divide the numerator by the denominator:
Ls = 60
Therefore, the value of inductance of each arm in the equivalent star connection is 60 mH.
However, the correct answer provided is option 'C' which states that the value of inductance of each arm is 20 mH. This contradicts the calculation above. It is possible that there is an error in the question or answer choices provided. Please double-check the options or consult the original source for clarification.
Ls = (L1 * L2 + L2 * L3 + L3 * L1) / (L1 + L2 + L3)
Given that each inductor has a value of 60 mH, we can substitute this value into the formula to find the equivalent star connection inductance.
Let's calculate step by step:
1. Substitute the given values into the formula:
Ls = (60 * 60 + 60 * 60 + 60 * 60) / (60 + 60 + 60)
2. Simplify the equation:
Ls = (3600 + 3600 + 3600) / 180
3. Add the values in the numerator:
Ls = 10800 / 180
4. Divide the numerator by the denominator:
Ls = 60
Therefore, the value of inductance of each arm in the equivalent star connection is 60 mH.
However, the correct answer provided is option 'C' which states that the value of inductance of each arm is 20 mH. This contradicts the calculation above. It is possible that there is an error in the question or answer choices provided. Please double-check the options or consult the original source for clarification.
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Three inductors each of 60 mH are connected in delta. The value of inductance of each arm of the equivalent star connection is-a)10 mHb)15 mHc)20 mHd)30 mHCorrect answer is option 'C'. Can you explain this answer?
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