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A flywheel for a punch press must be capable of furnishing 2.7 KJ of energy during the 1/4 revolution while the hole is being punched. The maximum speed of the flywheel is 200rev/min, and the speed decreases 10% during the cutting stroke. The mean radius of the rim is 915mm.
What should be the total mass of the flywheel,i.e.suming that the mass of the flywheel is 1.15 times that of the rim? It has also been assumed that The flywheel rim contributes only 90% of the energy requirement.
- a)69.6 kg
- b)80 kg
- c)149.6 kg
- d)172.84 kg
Correct answer is option 'B'. Can you explain this answer?
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To find the total mass of the flywheel, we need to consider the energy required, the speed, and the mean radius of the rim.
Given data:
Energy required during punching = 2.7 KJ
Maximum speed of the flywheel = 200 rev/min
Speed decreases by 10% during cutting stroke
Mean radius of the rim = 915 mm
Mass of the flywheel = 1.15 times the mass of the rim
Flywheel rim contributes only 90% of the energy requirement
Let's break down the solution into steps:
Step 1: Convert the given data into SI units
Energy required during punching = 2.7 KJ = 2.7 * 10^3 J
Maximum speed of the flywheel = 200 rev/min = 200 * 2π rad/s
Speed decreases by 10% = 0.9 * maximum speed
Step 2: Calculate the energy provided by the flywheel rim
Energy provided by the flywheel rim = 0.9 * 2.7 * 10^3 J
= 2430 J
Step 3: Calculate the distance traveled by the rim during the cutting stroke
Distance traveled by the rim during the cutting stroke = (1/4) * 2π * mean radius
= (1/4) * 2π * 915 mm = π * 915/2 mm
Step 4: Convert the distance into meters
Distance traveled by the rim during the cutting stroke = π * 915/2 * 10^-3 m
Step 5: Calculate the angular velocity during the cutting stroke
Angular velocity during the cutting stroke = speed during cutting stroke / mean radius
= (0.9 * maximum speed) / 915 mm
= (0.9 * 200 * 2π) / 915 rad/s
Step 6: Calculate the time taken for the cutting stroke
Time taken for the cutting stroke = distance traveled / angular velocity
= (π * 915/2 * 10^-3) / ((0.9 * 200 * 2π) / 915) s
Step 7: Calculate the kinetic energy of the flywheel rim during the cutting stroke
Kinetic energy of the flywheel rim = (1/2) * mass * (angular velocity)^2
We can rearrange the formula to find the mass of the flywheel:
Mass of the flywheel = (2 * Kinetic energy of the flywheel rim) / (angular velocity)^2
Step 8: Substitute the values and calculate the mass of the flywheel
Mass of the flywheel = (2 * 2430) / ((0.9 * 200 * 2π) / 915)^2 kg
= 79.789 kg
Since the mass of the flywheel is 1.15 times the mass of the rim:
Mass of the rim = 79.789 / 1.15 kg = 69.34 kg (approx.)
Therefore, the total mass of the flywheel should be approximately 80 kg (option B).
Given data:
Energy required during punching = 2.7 KJ
Maximum speed of the flywheel = 200 rev/min
Speed decreases by 10% during cutting stroke
Mean radius of the rim = 915 mm
Mass of the flywheel = 1.15 times the mass of the rim
Flywheel rim contributes only 90% of the energy requirement
Let's break down the solution into steps:
Step 1: Convert the given data into SI units
Energy required during punching = 2.7 KJ = 2.7 * 10^3 J
Maximum speed of the flywheel = 200 rev/min = 200 * 2π rad/s
Speed decreases by 10% = 0.9 * maximum speed
Step 2: Calculate the energy provided by the flywheel rim
Energy provided by the flywheel rim = 0.9 * 2.7 * 10^3 J
= 2430 J
Step 3: Calculate the distance traveled by the rim during the cutting stroke
Distance traveled by the rim during the cutting stroke = (1/4) * 2π * mean radius
= (1/4) * 2π * 915 mm = π * 915/2 mm
Step 4: Convert the distance into meters
Distance traveled by the rim during the cutting stroke = π * 915/2 * 10^-3 m
Step 5: Calculate the angular velocity during the cutting stroke
Angular velocity during the cutting stroke = speed during cutting stroke / mean radius
= (0.9 * maximum speed) / 915 mm
= (0.9 * 200 * 2π) / 915 rad/s
Step 6: Calculate the time taken for the cutting stroke
Time taken for the cutting stroke = distance traveled / angular velocity
= (π * 915/2 * 10^-3) / ((0.9 * 200 * 2π) / 915) s
Step 7: Calculate the kinetic energy of the flywheel rim during the cutting stroke
Kinetic energy of the flywheel rim = (1/2) * mass * (angular velocity)^2
We can rearrange the formula to find the mass of the flywheel:
Mass of the flywheel = (2 * Kinetic energy of the flywheel rim) / (angular velocity)^2
Step 8: Substitute the values and calculate the mass of the flywheel
Mass of the flywheel = (2 * 2430) / ((0.9 * 200 * 2π) / 915)^2 kg
= 79.789 kg
Since the mass of the flywheel is 1.15 times the mass of the rim:
Mass of the rim = 79.789 / 1.15 kg = 69.34 kg (approx.)
Therefore, the total mass of the flywheel should be approximately 80 kg (option B).
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A flywheel for a punch press must be capable of furnishing 2.7 KJ of energy during the 1/4 revolution while the hole is being punched. The maximum speed of the flywheel is 200rev/min, and the speed decreases 10% during the cutting stroke. The mean radius of the rim is 915mm.What should be the total mass of the flywheel,i.e.suming that the mass of the flywheel is 1.15 times that of the rim? It has also been assumed that The flywheel rim contributes only 90% of the energy requirement.a)69.6 kgb)80 kgc)149.6 kgd)172.84 kgCorrect answer is option 'B'. Can you explain this answer?
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A flywheel for a punch press must be capable of furnishing 2.7 KJ of energy during the 1/4 revolution while the hole is being punched. The maximum speed of the flywheel is 200rev/min, and the speed decreases 10% during the cutting stroke. The mean radius of the rim is 915mm.What should be the total mass of the flywheel,i.e.suming that the mass of the flywheel is 1.15 times that of the rim? It has also been assumed that The flywheel rim contributes only 90% of the energy requirement.a)69.6 kgb)80 kgc)149.6 kgd)172.84 kgCorrect answer is option 'B'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A flywheel for a punch press must be capable of furnishing 2.7 KJ of energy during the 1/4 revolution while the hole is being punched. The maximum speed of the flywheel is 200rev/min, and the speed decreases 10% during the cutting stroke. The mean radius of the rim is 915mm.What should be the total mass of the flywheel,i.e.suming that the mass of the flywheel is 1.15 times that of the rim? It has also been assumed that The flywheel rim contributes only 90% of the energy requirement.a)69.6 kgb)80 kgc)149.6 kgd)172.84 kgCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A flywheel for a punch press must be capable of furnishing 2.7 KJ of energy during the 1/4 revolution while the hole is being punched. The maximum speed of the flywheel is 200rev/min, and the speed decreases 10% during the cutting stroke. The mean radius of the rim is 915mm.What should be the total mass of the flywheel,i.e.suming that the mass of the flywheel is 1.15 times that of the rim? It has also been assumed that The flywheel rim contributes only 90% of the energy requirement.a)69.6 kgb)80 kgc)149.6 kgd)172.84 kgCorrect answer is option 'B'. Can you explain this answer?.
A flywheel for a punch press must be capable of furnishing 2.7 KJ of energy during the 1/4 revolution while the hole is being punched. The maximum speed of the flywheel is 200rev/min, and the speed decreases 10% during the cutting stroke. The mean radius of the rim is 915mm.What should be the total mass of the flywheel,i.e.suming that the mass of the flywheel is 1.15 times that of the rim? It has also been assumed that The flywheel rim contributes only 90% of the energy requirement.a)69.6 kgb)80 kgc)149.6 kgd)172.84 kgCorrect answer is option 'B'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A flywheel for a punch press must be capable of furnishing 2.7 KJ of energy during the 1/4 revolution while the hole is being punched. The maximum speed of the flywheel is 200rev/min, and the speed decreases 10% during the cutting stroke. The mean radius of the rim is 915mm.What should be the total mass of the flywheel,i.e.suming that the mass of the flywheel is 1.15 times that of the rim? It has also been assumed that The flywheel rim contributes only 90% of the energy requirement.a)69.6 kgb)80 kgc)149.6 kgd)172.84 kgCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A flywheel for a punch press must be capable of furnishing 2.7 KJ of energy during the 1/4 revolution while the hole is being punched. The maximum speed of the flywheel is 200rev/min, and the speed decreases 10% during the cutting stroke. The mean radius of the rim is 915mm.What should be the total mass of the flywheel,i.e.suming that the mass of the flywheel is 1.15 times that of the rim? It has also been assumed that The flywheel rim contributes only 90% of the energy requirement.a)69.6 kgb)80 kgc)149.6 kgd)172.84 kgCorrect answer is option 'B'. Can you explain this answer?.
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ample number of questions to practice A flywheel for a punch press must be capable of furnishing 2.7 KJ of energy during the 1/4 revolution while the hole is being punched. The maximum speed of the flywheel is 200rev/min, and the speed decreases 10% during the cutting stroke. The mean radius of the rim is 915mm.What should be the total mass of the flywheel,i.e.suming that the mass of the flywheel is 1.15 times that of the rim? It has also been assumed that The flywheel rim contributes only 90% of the energy requirement.a)69.6 kgb)80 kgc)149.6 kgd)172.84 kgCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice SSC tests.
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