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In a balanced 3-phase circuit, the line current is 12A. When the power is measured by two wattmeter method, one meter reads 11kW while the other reads zero. The power factor of the load is-
- a)0
- b)0.5
- c)0.866
- d)1.0
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
In a balanced 3-phase circuit, the line current is 12A. When the powe...
IL = 12A
View all questions of this test
WL = 11KW
W2 = 0
Φ = 600
Power factor = cos600 = ½ = 0.5
Most Upvoted Answer
In a balanced 3-phase circuit, the line current is 12A. When the powe...
Given:
Line current (IL) = 12A
One wattmeter reading (W1) = 11 kW
Other wattmeter reading (W2) = 0
To find: Power factor (PF)
Solution:
In a balanced 3-phase circuit, the power can be measured using two wattmeter method. The power is given by,
P = W1 + W2
For a balanced load, the power is equally distributed among the three phases,
P = 3VLILcos(θ)
where VL is the line voltage and θ is the phase angle between the voltage and current.
Using the two wattmeter method, the power can be expressed as,
P = (W1 - W2)/2
Substituting the given values,
11 kW = (W1 - 0)/2
W1 = 22 kW
Now,
cos(θ) = P/(3VLIL)
cos(θ) = 11 kW/(3VL x 12 A)
cos(θ) = 0.305
cos(θ) = PF
Therefore, the power factor of the load is 0.305.
Option B (0.5) is not the correct answer.
Line current (IL) = 12A
One wattmeter reading (W1) = 11 kW
Other wattmeter reading (W2) = 0
To find: Power factor (PF)
Solution:
In a balanced 3-phase circuit, the power can be measured using two wattmeter method. The power is given by,
P = W1 + W2
For a balanced load, the power is equally distributed among the three phases,
P = 3VLILcos(θ)
where VL is the line voltage and θ is the phase angle between the voltage and current.
Using the two wattmeter method, the power can be expressed as,
P = (W1 - W2)/2
Substituting the given values,
11 kW = (W1 - 0)/2
W1 = 22 kW
Now,
cos(θ) = P/(3VLIL)
cos(θ) = 11 kW/(3VL x 12 A)
cos(θ) = 0.305
cos(θ) = PF
Therefore, the power factor of the load is 0.305.
Option B (0.5) is not the correct answer.
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In a balanced 3-phase circuit, the line current is 12A. When the power is measured by two wattmeter method, one meter reads 11kW while the other reads zero. The power factor of the load is-a)0b)0.5c)0.866d)1.0Correct answer is option 'B'. Can you explain this answer?
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In a balanced 3-phase circuit, the line current is 12A. When the power is measured by two wattmeter method, one meter reads 11kW while the other reads zero. The power factor of the load is-a)0b)0.5c)0.866d)1.0Correct answer is option 'B'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about In a balanced 3-phase circuit, the line current is 12A. When the power is measured by two wattmeter method, one meter reads 11kW while the other reads zero. The power factor of the load is-a)0b)0.5c)0.866d)1.0Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a balanced 3-phase circuit, the line current is 12A. When the power is measured by two wattmeter method, one meter reads 11kW while the other reads zero. The power factor of the load is-a)0b)0.5c)0.866d)1.0Correct answer is option 'B'. Can you explain this answer?.
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