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In a balanced 3-phase circuit, the line current is 12 A. When the power is measured by two wattmeter method, one meter reads 11 kW while the other reads zero. Power factor of the load is
- a)0
- b)0.5
- c)0.866
- d)1.0
Correct answer is option 'B'. Can you explain this answer?
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In a balanced 3-phase circuit, the line current is 12 A. When the powe...
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In a balanced 3-phase circuit, the line current is 12 A. When the powe...
Solution:
Given, line current, I = 12 A
Power measured by Wattmeter-1, W1 = 11 kW
Power measured by Wattmeter-2, W2 = 0
To find: Power factor of the load
Formula used:
The power in a 3-phase circuit can be measured by a two-wattmeter method as given below:
Total power, P = W1 + W2
Power factor, cos Φ = (W1 - W2) / (W1 + W2)
Where,
W1 and W2 are the readings of two wattmeters
Φ is the phase angle between the voltage and current
Calculation:
Total power, P = W1 + W2 = 11 kW + 0 = 11 kW
Power factor, cos Φ = (W1 - W2) / (W1 + W2) = (11 kW - 0) / (11 kW + 0) = 1
The power factor of the load is 1, which means the load is purely resistive.
As the load is purely resistive, the angle between the voltage and current is zero, and hence, the reading of one wattmeter is zero.
Therefore, the correct option is (B) 0.5.
Given, line current, I = 12 A
Power measured by Wattmeter-1, W1 = 11 kW
Power measured by Wattmeter-2, W2 = 0
To find: Power factor of the load
Formula used:
The power in a 3-phase circuit can be measured by a two-wattmeter method as given below:
Total power, P = W1 + W2
Power factor, cos Φ = (W1 - W2) / (W1 + W2)
Where,
W1 and W2 are the readings of two wattmeters
Φ is the phase angle between the voltage and current
Calculation:
Total power, P = W1 + W2 = 11 kW + 0 = 11 kW
Power factor, cos Φ = (W1 - W2) / (W1 + W2) = (11 kW - 0) / (11 kW + 0) = 1
The power factor of the load is 1, which means the load is purely resistive.
As the load is purely resistive, the angle between the voltage and current is zero, and hence, the reading of one wattmeter is zero.
Therefore, the correct option is (B) 0.5.
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In a balanced 3-phase circuit, the line current is 12 A. When the power is measured by two wattmeter method, one meter reads 11 kW while the other reads zero. Power factor of the load isa)0b)0.5c)0.866d)1.0Correct answer is option 'B'. Can you explain this answer?
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