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The voltage across a load is v(t) = 60 ωt-10cos V and the current through the load in the direction of the voltage drop is i(t) = 1.5cos(ωt+50)A. The reactive power is
  • a)
    27.62 VAR leading
  • b)
    38.97 VAR leading
  • c)
    38.97 VAR lagging
  • d)
    none of the above
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The voltage across a load is v(t) = 60ωt-10cos V and the current...
The r.m.s. values of voltage and current phasors are:


Therefore, reactive power = 38.97 VAR, leading because reactive power is negative.
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Most Upvoted Answer
The voltage across a load is v(t) = 60ωt-10cos V and the current...
Cos(120πt) V.

This equation describes an alternating current (AC) voltage signal with a frequency of 60 Hz. The amplitude of the signal is 60 V, and it oscillates between positive and negative values at a rate of 120 cycles per second. The waveform of this signal is a sinusoidal curve, with a period of 1/60 seconds (or 16.7 milliseconds).

The load that this voltage is applied to will experience an alternating current that varies in amplitude and direction over time. The behavior of the load will depend on its characteristics and the properties of the signal, such as its frequency and amplitude. For example, a resistor will experience a current that is proportional to the voltage, while a capacitor or inductor will exhibit different behavior due to their reactive properties.

Overall, this equation provides important information about the properties of the voltage signal, which can be useful in designing and analyzing electrical systems.
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The voltage across a load is v(t) = 60ωt-10cos V and the current through the load in the direction of the voltage drop isi(t) = 1.5cos(ωt+50)A. The reactive power isa)27.62 VAR leadingb)38.97 VAR leadingc)38.97 VAR laggingd)none of the aboveCorrect answer is option 'B'. Can you explain this answer?
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