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In a transformer maximum efficiency occurs at 80% of a full load then what is the Relation between ironless at rated voltage (Pi) and copper loss full load.
  • a)
    25Pi = 16Pc
  • b)
    20Pi = 16Pc
  • c)
    18Pi = 7Pc
  • d)
    21Pi = 20Pc
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
In a transformer maximum efficiency occurs at 80% of a full load then ...
At maximum efficiency
Pc = Pi
Copper loss at 70% of full load
= (0.8)2 Pc
Iron loss at rated voltage = Pi
Pi = (0.8)2Pc
Pi=16/25Pe
25 Pi = 16 Pc
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Most Upvoted Answer
In a transformer maximum efficiency occurs at 80% of a full load then ...

Relation between iron loss at rated voltage and copper loss at full load:

Iron loss (Pi) and copper loss (Pc) are the two main components of losses in a transformer. The relationship between these two losses can be determined using the given information that maximum efficiency occurs at 80% of full load.

Efficiency of a transformer:
Efficiency (η) = Output power / Input power = (Output power / (Output power + Losses))

Given:
Efficiency is maximum at 80% of full load, so input power = output power + losses at 80% full load.

Relation between losses at full load:
Let Pi be the iron loss at rated voltage and Pc be the copper loss at full load.

At 80% of full load, losses = Pi + 0.8^2 * Pc
At full load, losses = Pi + Pc

Equating the two expressions:
Pi + 0.8^2 * Pc = Pi + Pc
0.64Pc = Pi

Relation:
25Pi = 16Pc

Therefore, the correct relation between iron loss at rated voltage (Pi) and copper loss at full load is 25Pi = 16Pc.
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In a transformer maximum efficiency occurs at 80% of a full load then what is the Relation between ironless at rated voltage (Pi) and copper loss full load.a)25Pi = 16Pcb)20Pi = 16Pcc)18Pi = 7Pcd)21Pi = 20PcCorrect answer is option 'A'. Can you explain this answer?
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